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Scrat [10]
3 years ago
7

Oil is leaking from a tanker at the rate of R(t) = 2000e^(-0.2t) gallons per hour where t is measured in hours. How much oil lea

ks out of the tanker from the time t = 0 to t = 10
...?
Mathematics
1 answer:
Kipish [7]3 years ago
6 0
The calculation of the integral will give us the answer.

Amount = Int (2000e^(-0,2t))dt

With t = 0 to t = 10

A = 2000.In(e^(-0,2t))dt


Making U = -0,2t

U = -0,2t

dU/dt = d(-0,2t)/dt

dU/dt = -0,2

dU = -0,2dt

dt = dU/-0,2
_______________


Then,

A = 2000.Int (e^U).dU/-0,2

A = -10.000.Int(e^U)dU

A = -10.000.e^U

A = -10.000.e^(-0,2t) | (0,10)

A = -10.000.(e^(-2)) - [ -10.000.e^(0)]

A = -10.000.e^(-2) + 10.000

A ~ 8,646 Gallons


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Five men can install 200 yards of pipeline in an eight hour day three men are added to the job assuming the individuals rates re
Novay_Z [31]

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7 days

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3 0
3 years ago
An office has 150 employees, and 30 of the employees work the night shift. What percentage of the employees work the night shift
Zanzabum
<h2>Answer:</h2>

The percent of employees who work in the night shift are:

                                     20%

<h2>Step-by-step explanation:</h2>

Total number of employee in the office are: 150

Number of employee who work in the night shift are:  30

The percent of the employee who work in the night shift is calculated as follows:

\dfrac{\text{Number\ of\ people\ working\ in\ the\ night\ shift}}{\text{Total\ number\ of\ employees}}\times 100

Hence, on putting the value in the above formula we get:

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                          20%

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3 years ago
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