1) C 2) B I hope this helps!
x - 5y = -5, -5x - 25y = 25
First, you'll need to get the x variable by itself.
x - 5y = -5<u>
</u><u> +5 +5</u><u>
</u> x = 0
So x is plotted on the 0.
For the second part of the first equation, you'll be looking for what the y variable represents.
x - 5y = -5
<u>-x -x</u><u>
</u> <u>-5y</u> = <u>-5</u><u>
</u><u> 5 5</u><u>
</u> y = 1
So y is plotted on the 1 on the vertical line above the 0.
For the first part of the second equation, you'll do the same thing as in the first equation.
-5x - 25y = 25
<u> +25 +25</u><u>
</u> <u>-5x</u> = <u>50</u><u>
</u> 5 5
x = 10
So the x for this equation is plotted on 10 on the horizontal line.
For the second part of the second equation, you will do the same thing as in the first equation.
-5x - 25y = 25
<u>+5 +5</u><u>
</u> <u>-25y</u> = <u>30</u><u>
</u> 25 25
y = 1.2
So the y for the second half of the second question is plotted on 1.2 on the vertical line.
<h2>
Answer: B) Perpendicular</h2>
Perpendicular means the lines may or may not be of equal length and they will not be perfectly in line with each other.
Parallel means the lines may or may not be of equal length but will be perfectly in line with each other.
Intersecting means the lines may or may not be of equal length but will touch each other.
For the answer to the question above asking to p<span>rove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle,
</span>A right triangle consists of two sides called the legs and one side called the hypotenuse (c²) . The hypotenuse (c²)<span> is the longest side and is opposite the right angle.
</span>⇒ α² + β² = c²
<span>
"</span>In any right triangle ( 90° angle) <span>, the sum of the squared lengths of the two legs is equal to the squared length of the hypotenuse."
</span>
For example: Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are 3 inches and 4 inches.
c2 = a2+ b2
c2 = 32+ 42
c2 = 9+16
c2 = 15
c = sqrt25
c=5
Answer:
Step-by-step explanation:
A” (-2,2)
B” (-1,-2)
C” (-4,-4)
