3 years ago

James saved £15 per week for 100 weeks. How much did he have? How much would he have after 2 years

1 answer:

7 0

£15 × 100 = £1500 is what currently has

a year normally has about 52 weeks, so 2 years have 104 weeks

£15 × 104 = £1560

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Reduce 36/45 to lowest terms and write the numerator in the blank.

saveliy_v [14]

4/5 is your answer

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3 years ago

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A cone has a volume of 6782.4 cubic centimeters and a radius of 18 centimeters. What is its height?

ELEN [110]

Answer: 19.99cm

Step-by-step explanation: trust

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2 years ago

This is a square pyramid. What is the length of the base? h=3 v=36

Ulleksa [173]

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3 years ago

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3 years ago

A randomly selected sample of n =51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years. Calc

Aloiza [94]

Answer:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

Step-by-step explanation:

Information given

$\bar X= 59$ represent the sample mean

$s= 10$ represent the sample deviation

$n= 51$ represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=51-1=50$

The Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.01$ ,and the critical value would be $t_{\alpha/2}=2.40$

And replacing we got:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

3 0

3 years ago