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klasskru [66]
4 years ago
5

MULTIPLE CHOICE!!!

Computers and Technology
2 answers:
kolbaska11 [484]4 years ago
8 0
The answer is a) you
bixtya [17]4 years ago
6 0

Answer: The Government

Explanation:

You might be interested in
5. Create a variety of test cases focusing on the sorting algorithm, such as the final element is the smallest, the entire set i
andrew11 [14]

Answer:

// C code

// This code will compute the values of the sales ticket sales for concerts

#include <stdio.h>

#define MAXN 100 // max characters in a group/concert name

#define MAXG 50 // max concerts/groups

#define MAXC 3 //max categories

char group [MAXG][MAXN];

int fans [MAXG][MAXC];

float prices [MAXC];

float sales [MAXG];

int count = 0;

void printArray () {

printf ("%15s%5s%5s%5s%10s\n",

"Concert", "s1", "s2", "s3","Sales");

for (int i = 0; i < count; i++) {

printf ("%15s", group [i]);

for (int j = 0; j < MAXC; j++) {

printf ("%5d", fans[i][j]);

} // end for each category

printf ("%10.2f\n", sales [i]);

} // end for each group

} // end function printArray

void computeSales () {

for (int i = 0; i < count; i++) {

sales [i] = 0;

for (int j = 0; j < MAXC; j++) {

sales [i] += prices [j] * fans [i][j];

} // end for each category

} // end for each group

} // end function computeSales

// ***** totalSales ****

void totalSales()

{

float tsales;

for(int i = 0; i <= MAXC; i++){

tsales += sales [i];

}

printf("\n\t\tThe total sales are: $%.2f\n",tsales);

}

// ***********************************

void switchRows (int m, int n) {

char tc;

int ti;

float v;

// printf ("Switching %d with %d\n", m, n);

for (int i = 0; i < MAXN; i++) {

tc = group [m][i];

group [m][i] = group [n][i];

group [n][i] = tc;

} // end for each character in a group name

for (int i = 0; i < MAXC; i++) {

ti = fans [m][i];

fans [m][i] = fans [n][i];

fans [n][i] = ti;

} // end for each fan category

v = sales [m];

sales [m] = sales [n];

sales [n] = v;

} // end switch

int findMinSales (int m) {

float min = sales [m];

int target = m;

for (int i = m+1; i < count; i++)

if (sales [i] < min) {

min = sales [i];

target = i;

} // end new max found

return target;

} // end function findMinSales

void sortBySales () {

int target;

for (int i = 0; i < count; i++) {

target = findMinSales (i);

if (target > i)

switchRows (i, target);

} // for each concert

} // end function sortBySales

//**********sort by fans*************

int minFans (int b) {

float min = fans [b][0];

int target = b;

for (int i = b; i < count; i++)

if (fans [i][0] < min) {

min = fans [i][0];

target = i;

} // end new max found

return target;

}

void sortByFans () {

int target = 0;

//int result;

 

for (int i = 0; i < count; i++) {

target = minFans(i);

if (target > i)

//result = target;    

switchRows (i,target);

 

}

}

//********************************

void getData () {

// for (int i = 0; i < MAXG; i++) sales [i] = 0;

printf ("\nEnter ticket prices in each of %d cateogories: ", MAXC);

for (int i = 0; i < MAXC; i++)

scanf ("%f", &prices [i]);

printf ("-- Enter group and fans in %d categories\n", MAXC);

printf (" . to finish entries:\n");

for (int i = 0; i < MAXG; i++) {

scanf ("%s", group[i]);

if (group [i][0] == '.')

break;

count++;

for (int j = 0; j < MAXC; j++)

scanf ("%d", &fans[i][j]);

} // end for each group

} // end function getData

int main(void) {

getData ();

computeSales ();

printArray ();

printf ("\n --- Sorted sales ---\n");

sortBySales ();

printArray ();

totalSales ();

printf("--- sorted by fans ---\n");

sortByFans ();

printArray ();

totalSales ();

printf("\t\t ... Bye ...\n");

return 0;

}

7 0
4 years ago
This is a python program.
denpristay [2]

Answer:

word = input("Type your name: ")

print(len(word))

Explanation:

The len function will count all the chars in the string.

7 0
3 years ago
Which heading size fits for the word headings​
hjlf
The first one h4 is yhat
3 0
3 years ago
Read 2 more answers
Create a new Die object. (Refer to Die.html for documentation.)Create a loop that will iterate at least 100 times. In the loop b
hjlf

Answer:

Java code is given below

Explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

}

8 0
4 years ago
F1: 2^14 formula ....................................................................
QveST [7]

Answer:

=POWER(2,14)

Explanation:

The complete question is to write the given formula in cell F1

We have:

F1 = 2^\wedge {14}

The above formula implies 2 raised to the power of 14.

In Excel, this can be achieved using the power function

And the syntax is:

=POWER(m,n)

which means m^n

So, 2^14 will be entered in cell F1 as:

=POWER(2,14)

4 0
3 years ago
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