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umka2103 [35]
3 years ago
14

PLEASE ANSWER FAST!!!

Mathematics
1 answer:
krok68 [10]3 years ago
8 0
The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
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Slimplify 14^0+2^7+15^1=
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Answer:

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