Answer:
csc (0°) and sec (90°) are not defined.
Step-by-step explanation:
Given the options wehave to select the option which is undefinesd
First option: sec 45°
which is defined
Second option: csc(0°)
which is not defined
Third option: sec(90°)
which is not defined.
Hence, option 2 and 3 are not defined.
What is the cost of the bond?
When you see that a bond was purchased "at 92", this means that the bond was purchased for 92% of the face value. Sometimes the bond purchaser will pay more than the face value (purchased a number greater than 100), generally if the interest rate is higher than the market rate.
The cost of one bond, then, is 92% of 1,000, or $920.
Since there are 6 bonds, the total cost is 920 x 6 = $5520
What is the total annual interest?
The annual interest is the interest rate on the bond times the face value (not the cost of the bond).
The interest rate is 6.5%, so the annual interest on one bond is:
6.5% x 1000 = $65
6 bonds: $65 x 6 = $390
When we think of yield, we want to consider the real return on the bond. This is the annual interest earned divided by what the purchaser paid for it.
The purchaser paid $5520 for the bonds, and is earning $390.
390 ÷ 5520 = 7.06%.
Note that we can also calculate the return on one bond, rather than the total cost and interest of 6 bonds, and get the same result.
65 ÷ 920 = 7.06%
Answer:
-8
Step-by-step explanation:
Answer:
GCF of 32 and 80 is 16
Step-by-step explanation:
factors of 32 = 1, 2, 4, 8, 16, 32
factors of 80 = 1, 2, 4, 5, 8, 10, 16, 20, 40, 80
This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.
Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6
Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2
The magnitudes of the two forces are 2N and 3N, in no particular order.
