Answer:
2x^4-11x^3+68x-80
2x^4-4x^3-7x^3+14x^2-14x^2+28x+40x-80
2x^3(x-2)-7x^2(x-2)-14x(x-2)+40(x-2)
(x-2)(2x^3-7x^2-14x+40)
(x-2)(2x^3-4x^2-3x^2+6x-20x+40)
(x-2)(2x^2(x-2)-3x(x-2)-20(x-2))
(x-2)(x-2)(2x^3-3x-20)
(x-2)(x-2)(2x^2+5x-8x-20)
(x-2)(x-2)(x(2x+5)-4(2x+5))
(x-2)(x-2)(2x+5)(x-4)
(x-2)^2(2x+5)(x-4)
Answer:
2.46×10^8
Step-by-step explanation:
The decimal point is here
246000000.
Then it must be moved up to here
2.46000000
Those are eight steps from where it was, so to compensate and make sure the number remains the same remove the zeros and multiply by 10^8
Then you have
2.46×10^8
1/2. It isn't asking for another solution, just the fraction.
Hope this helps!
Answer:
9 = X -1 X = 10
Step-by-step explanation:
Add one to both sides
Solution:
Total number of Days that Pooja's plant survived= 2 + 98 = 100 Days=(t)
Longest Height obtained by plant = 30 cm= h
As the two , i.e number of Days lived by plant and it's longest height obtained are directly proportional.
We will solve it by unitary method.
100 Days = 30 cm
1 cm = Days
If height of the plant is h cm ,and amount of time taken is t days, then
h(t) cm = ,for t=0,1,2,3,4,5,6....we get different values of h.
