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3 years ago

Round your answer to two decimal places log 6e

Mathematics

1 answer:

Andru [333]3 years ago

4 0

Solution: We know that e is numerical constant and is equal to 2.71828.

Therefore log( 6 x 2.71828) = 1.21

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The moon has a shape of what geometric solid?

Alex777 [14]

The moon is a sphere. 

3 0

4 years ago

A large poll showed that 42%, percent of adults approved of their nation's prime minister. Margot wants to test if it is now low

harina [27]

According to the situation described, the appropriate set of hypotheses for her significance test is given by:

$H_0: p = 0.42$ .

$H_1: p < 0.42$ .

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the proportion is still of 42%, that is:

$H_0: p = 0.42$ .

At the alternative hypothesis, it is tested if the proportion is now lower, that is:

$H_1: p < 0.42$ .

Hence, the the appropriate set of hypotheses for her significance test is given by:

$H_0: p = 0.42$ .

$H_1: p < 0.42$ .

More can be learned about an hypothesis test at brainly.com/question/26454209

5 0

2 years ago

Slove the system of equations:y+4×=8and 5×+2y=13?

In-s [12.5K]

I am gonna use substitution method.
Solve for y in first equation,
y + 4x = 8
y = 8 -4x
Put the above y value in second equation,
5x + 2y = 13
5x + 2(8-4x) = 13
5x + 16 - 8x = 13
-3x = 13-16
-3x = -3
x = -3/-3
x = 1/1 = 1
Put the x value in first equation,
y + 4x = 8
y + 4(1) = 8
y = 8 - 4
y = 4
Hence, the solution is (1,4)

7 0

4 years ago

Please help!!! I.m confused with the problem

Oxana [17]

Answer:

Step-by-step explanation:

Make the equation from the blocks:

-7x + 7 = 5x + 16

Then simplify:

Subract 7 from both sides:

-7x = 5x + 9

Add 7x:

0 = 12x + 9

Subtract 9:

-9 = 12x

x = -9/12 = -3/4

7 0

4 years ago

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}$

3 0

4 years ago