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Ostrovityanka [42]
3 years ago
7

The perpendicular bisectors of ΔPQR intersect at point A as shown in the diagram. What is the radius of the circumscribed circle

of ΔPQR?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
The answer to this is 9.22
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The Answer is Together
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3 years ago
Mrs. Evans gave her class a 100-page reading assignment. After 2 days, Kya and
Zarrin [17]

Answer:

so the answer is 20 because u know how she take it for days

4 0
2 years ago
I need to know how to solve it and get the answer right to check my work
Ede4ka [16]
Solve it by finding out how many times 22 can be put into 22, which is once, so the answer is 1.
3 0
3 years ago
Read 2 more answers
The courtyard outside East Middle School is in the shape of a rectangle and half-circle.
Nadya [2.5K]

Answer:

The correct option is the third one counting from the top. (5892 m^2)

Step-by-step explanation:

First, we need to remember that:

For a rectangle of length L and width W, the area is:

A = L*W

For a circle of diameter D, the area is:

A = pi*(D/2)^2

Where pi = 3.14

In the image, we can see a rectangle and half a circle, the total area of the image will be equal to the area of the rectangle plus the area of the half circle.

In the image, we can see a rectangle of length L = 100m and width W = 50m

Then the area of the rectangle is:

A = 100m*50m = 5000m^2

And we can see that for the half-circle the diameter is D = 50m

Note that the area of a half-circle is half of the area of a complete circle, then the area of that half-circle is:

A = (1/2)*(3.14*(50m/2)^2) = 981.25 m^2

If we add these two areas we get:

Total area =  5000m^2 + 981.25 m^2 = 5981.25 m^2

If we round it up, we get:

Total area = 5982 m^2

The correct option is the third one counting from the top.

8 0
2 years ago
2x+5(x+1) = -8;<br><br> Can someone help me solve this problem step by step please?
mariarad [96]

Answer:

-13/7

Step-by-step explanation:

2x+5(x+1)=-8

2x+5x+5=-8

7x+5=-8

7x=-8-5

7x=-13

7x/7=-13/7

x=-13/7

4 0
2 years ago
Read 2 more answers
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