All categories

2 years ago

Write an equation in slope-intercept form of the line that passes through (-5, 19) and (5.13).

Mathematics

1 answer:

ruslelena [56]2 years ago

3 0

Answer:

y=-3/5x+16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(13-19)/(5-(-5))

m=-6/(5+5)

m=-6/10

simplify

m=-3/5

y-y1=m(x-x1)

y-19=-3/5(x-(-5))

y-19=-3/5(x+5)

y=-3/5x-15/5+19

y=-3/5x-3+19

y=-3/5x+16

You might be interested in

Mikes plumbing charges 68 for coming to your house and 17 per hour for labor if I paid him 357, how many hours, h, was mike at m

Roman55 [17]

Answer:

b. $68 + 17h = 357$

f. 17 hours

Step-by-step explanation:

Charges for coming to my house = $68 (this will be the constant of the equation)

Amount charged per hour labor = $17

hours = h

Total amount paid to Mike = 357

The equation that represents this situation can be expressed as:

$68 + 17h = 357$

Solve for h

$68 + 17h - 68 = 357 - 68$ (subtraction property of equality)

$17h = 289$

$\frac{17h}{17} = \frac{289}{17}$ (division property of equality)

$h = 17$

Mike was in my house for 17 hours.

5 0

2 years ago

On which number line are −4 and its opposite shown?

Natasha2012 [34]

Answer:

it is D because it is asking for the opposite of -4 so it would be the tick mark on -4 and 4

Step-by-step explanation:

5 0

2 years ago

What is the solution of the following trig equation: tan(theta)(csc(theta)+2)=0

gtnhenbr [62]

$D:\theta\neq\frac{k\pi}{2};\ k\in\mathbb{Z}\\\\tan\theta(csc\theta+2)=0\iff tan\theta=0\ \vee\ csc\theta+2=0\\\\\\tan\theta=0\iff\theta=k\pi\notin D\\\\csc\theta+2=0\\\\csc\theta=-2\\\\\frac{1}{sin\theta}=-2\\\\-2sin\theta=1\ /:(-2)\\\\sin\theta=-\frac{1}{2}$

$(\theta=-\frac{\pi}{6}+2k\pi\ \vee\ \theta=\frac{7\pi}{6}+2k\pi)-answer$

7 0

3 years ago

Find the future value of the principal.<br>help me pls :(

Vitek1552 [10]

Answer:

54,000

Step-by-step explanation:

30,000/8% then multiply the answer by 10 than add that to 30,000

3 0

2 years ago

The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation

Olegator [25]

You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or 4k - 1 = 13. Then 4k = 14, and k = 14/4, or (after reduction) k = 7/2

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.

3 0

3 years ago