Answer:
See below
Step-by-step explanation:
I will assume the given denominator is 3a as there is nothing attached to the statement.
Lets first look at the domain of 2a+b. As it is a polynomial with unknowns a and b, we know it has its domain in all real numbers for both a and b as every polynomial does. For verifying it replace a and b by any real number you can think of.
Domain = a, b belonging to R
Now, if we divide 2a+b by 3a we will have:
(2a+b)/3a
As know we don not have a polynomial we cant state that the domain will still be all the real numbers for sure. We need to go further.
We have a fraction and as every fraction the denominator CAN'T be equal to 0, so 3a MUST be different to 0. This means that a MUST be different to 0. So, now our domain changes:
domain' = a, b belonging to R and a different to 0.
Answer: $117.59
Step-by-step explanation:
Answer:
(0.5, 0) will be the midpoint by applying formula which is
add both "x" quadrant and divide by it by two and then add both "you" quadrant and then divide it also by 2 you will get answer
