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3 years ago

6 1 2 3 + + 2 3 4 Situation: Find the value of this fraction computation: 6(1/2+3/4+2/3)

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

Answer:

11.5 gotchu 100% correct

Step-by-step explanation:

mina [271]3 years ago

6 0

Answer:

$\frac{23}{2}$ or 11.5

Step-by-step explanation:

$\frac{1}{2} + \frac{3}{4} + \frac{2}{3} = \frac{6}{12} + \frac{9}{12} + \frac{8}{12}$
Plug the new expression in: 6(6/12 + 9/12 + 8/12)
6/12 + 9/12 + 8/12 = 23/12
Plug 23/12 in: 6(23/12)
6(23/12) = 23/2 = 11.5

I hope this helps!

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In a certain state's lottery, 40 balls numbered 1 through 40 are placed in a machine and 7 of them are drawn at random. If the 7

DENIUS [597]

Answer:

Step-by-step explanation:

From the given information;

The total number of ways to choose 7 number = $^{40}C_7$

Number of ways to choose 7 correct numbers = $^{7}C_7$

∴

The probability P( win $2500000) is;

$= \dfrac{^{7}C_7}{^{40}C_7}$

$= \dfrac{\dfrac{7!}{7!(7-7)!} }{\dfrac{40!}{7!(40-7)!}}$

$= \dfrac{1 }{\dfrac{40!}{7!(40-7)!}}$

$= \dfrac{1 }{\dfrac{40!}{7!(33)!}}$

$= \dfrac{1 }{18643560}$

= 5.36 × 10⁻⁸

The probability P( win $10000) is:

$= \dfrac{^7C_5 \times ^{33} C_2}{^{40}C_7}$

$= \dfrac{ \dfrac{7!}{5!(7-5)!} \times \dfrac{33!}{2!(33-2)!} }{ \dfrac{40!}{7!(40-7)!}}$

$= \dfrac{ \dfrac{7!}{5!(2)!} \times \dfrac{33!}{2!(31)!} }{ \dfrac{40!}{7!(33)!}}$

$= \dfrac{ 21 \times 528 }{ 18643560}$

$= \dfrac{ 11088 }{ 18643560}$

$=\dfrac{462}{776815}$

= 5.95 × 10⁻⁴

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3 years ago

Factoring Gcf -2x^2-2x+84

marin [14]

Answer:

Step-by-step explanation:

The factors of the three terms are ...

(-1)(2)(x)(x)

(-1)(2)(x)

(2)(2)(3)(7)

The only common factor is 2.

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The expression can be factored as ...

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3 years ago

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Tanzania [10]

I’ve attached the answer .;.;

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The sum of a number and two is equal to eight

Virty [35]

Answer:

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Step-by-step explanation:

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3 years ago

6 1 2 3 + + 2 3 4 Situation: Find the value of this fraction computation: 6(1/2+3/4+2/3)​

6 1 2 3 + + 2 3 4 Situation: Find the value of this fraction computation: 6(1/2+3/4+2/3)