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3 years ago

Justin buys candy that cost 6$ per pound he will spend at most $66 on candy what are the possible numbers of pounds he will buy

1 answer:

4 0

If each pound costs six dollars, and you have $66 available, you have to think: how many six-dollar pounds will fit in $66. That is 66 divided by 6. ANSWER: 11 pounds.

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If 75% of a full budget is $1,200, what is the full budget? Using a table

Zepler [3.9K]

Answer:1600

Step-by-step explanation:

75/1200=100/x

75x=120000

/75

×=1600

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3 years ago

Which of the following best describes the slope of the line below? pls help asap

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

Undefined.

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2 years ago

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0: Shelby set a goal to run 3.1 miles. Today she ran 2.6 miles. What percent of her goal did she run?

alukav5142 [94]

Answer:

83.8% or 84%

Step-by-step explanation:

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3 years ago

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What times 27equals 216

svlad2 [7]

27 time 8 equals 216
...
216 divided by 27 equals 8

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3 years ago

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago