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4 years ago

(x+3)+49=90 how would I solve for x

Mathematics

2 answers:

tiny-mole [99]4 years ago

3 0

Answer:

38=x

Step-by-step explanation:

Isolate x. Subtract 49 from both sides, so we would get x+3=41, then subtract 3, so we sould get x=38

Eva8 [605]4 years ago

3 0

Answer:

x+3+49=90

x+52=90

x = 90-52

x = 38

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What is a fraction of a fraction

Vikentia [17]

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➷ When it comes to dividing fractions, there is a rule you must now.

It's called Keep Flip Change.

I'll give you an example:

$\frac{2}{7} / \frac{4}{6}$

Keep the first fraction exactly as it is

Flip the second fraction upside down (switch the numerator and denominator around)

Change the sign to a multiplication.

This is how it should look:

$\frac{2}{7} *\frac{6}{4}$

Now you just multiply them as you normally would to get an answer of:

$\frac{12}{28}$

➶Hope This Helps You!

➶Good Luck :)

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3 years ago

You have a bag filled with cones.There are an equal amount of blue,yellow, green, purple, and grey conesin the bag. You pull out

Leni [432]

B because it’s the right answer

7 0

4 years ago

John kicked the soccer ball 22 yards 1 foot in the last game . Today, he kicked the ball 13 yards 2 feet. How many feet did john

german

It would be 35 yards (22+13=35 yards) 1+2=3 feet

6 0

3 years ago

5. Find the first, fourth, and tenth terms of the arithmetic

Lubov Fominskaja [6]

The first, fourth and tenth terms of the arithmetic sequence is $-6, -\frac{27}{5}$ and $-\frac{21}{5}$

Explanation:

The given rule for the arithmetic sequence is $A(n)=-6+(n-1)(\frac{1}{5} )$

We need to determine the first, fourth and tenth terms of the sequence.

To find the first, fourth and tenth terms, let us substitute $n=1,4,10$ in the general rule for the arithmetic sequence.

To find the first term, substitute $n=1$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(1)=-6+(1-1)(\frac{1}{5} )$

$A(1)=-6+(0)(\frac{1}{5} )$

$A(1)=-6$

Thus, the first term of the arithmetic sequence is -6.

To find the fourth term, substitute $n=4$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(2)=-6+(4-1)(\frac{1}{5} )$

$A(2)=-6+(3)(\frac{1}{5} )$

$A(2)=\frac{-30+3}{5}$

$A(2)=\frac{-27}{5}$

Thus, the fourth term of the arithmetic sequence is $-\frac{27}{5}$

To find the tenth term, substitute $n=10$ in $A(n)=-6+(n-1)(\frac{1}{5} )$ , we get,

$A(10)=-6+(10-1)(\frac{1}{5} )$

$A(10)=-6+(9)(\frac{1}{5} )$

$A(10)=-6+\frac{9}{5}$

$A(10)=-\frac{21}{5}$

Thus, the tenth term of the arithmetic sequence is $-\frac{21}{5}$

Hence, the first, fourth and tenth terms of the arithmetic sequence is $-6, -\frac{27}{5}$ and $-\frac{21}{5}$

3 0

4 years ago

Find Volume for the cones. Round to the nearest TENTH. (A) Radius of 2 in, and a height of 4 inches (B) Diameter of 6 m, and a h

Aleksandr-060686 [28]

Answer:

A. 16.8 in³

B. 28.3 m³

C. 65.4 in³

Step-by-step explanation:

The volume of a cone is given as:

V = ⅓ * pi * r² * h

Where r = radius of base of cone

h = height of cone

A. Radius = 2 inches, height = 4 inches

It's volume is:

V = ⅓ * pi * 2² * 4

V = 16.8 in³

B. Diameter of 6 m, and a height of 3 m

It's diameter is 6 m, therefore, it's radius is:

r = d / 2 = 6 / 2 = 3 m

It's volume is:

V = ⅓ * pi * 3² * 3

V = 28.3 m³

C. Diameter of 5 in, and a height of 10 in

It's diameter is 5 in, therefore, it's radius is:

r = d / 2 = 5 / 2 = 2.5 m

It's volume is:

V = ⅓ * pi * 2.5² * 10

V = 65.4 in³

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3 years ago