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zavuch27 [327]
3 years ago
14

Express the function graphed on the axes below as a piecewise function.

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

y = 2/3x +6  for x< -3

y = 2/3x +1     for x> 3

Step-by-step explanation:

The graph is a line for  x < -3

( - 6,2) and ( -3,4)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point ( -6,2)

y -2 = 2/3(x - -6)

y -2 = 2/3(x +6)

y-2 = 2/3 x +4

y = 2/3x +6 x< -3

The graph is a line for  x > 3

(3,3) and ( 6,5)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 5-3)/(6-3) = 2/ (3) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point (6,5)

y -5 = 2/3(x - 6)

y-5 = 2/3 x -4

y = 2/3x +1   x> 3

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Find the area of the figure <br> A)75in^2<br> B)70in^2<br> C)65in^2<br> D)80in^2
katrin2010 [14]

Answer: B, 70 inches.

Step-by-step explanation:

Let's start slow and go shape by shape.

Based on the information we have, we know that the length for the rectangle is 8 inches by 7 inches. 8*7 = 56, so we have one of the answers.

Next, we do the triangle. Based on the information we have, we know that the triangle is 4 inches by 7 inches divided by 2. 4*7 = 28 \frac {28}{2} = 14

Adding 14 and 56, we got the answer to be B, 70 inches.

3 0
4 years ago
Robert jogged 1 2/5 km.his brother jogged 2 1/2 km.Who jogged the longer distance ?how much longer?
jolli1 [7]

His brother jogged more by 1 1/10 kilometers.  

5 0
3 years ago
If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

5 0
3 years ago
Can someone help me with this plz
Naily [24]

A. 3n + 4

First Four Terms: 7, 10, 13, 16

Tenth Term: 34:

Plug in 10, 3 x 10 = 30 + 4 = 34

B. 4n - 5

First Four Terms: -1, 3, 7, 11

Tenth Term: 35

Plug in 10, 4 x 10 = 40 - 5 = 35

3 0
3 years ago
Given line x is parallel to line y and m∠2 = 23°. What is m∠7? 23° 67° 157°
Anna007 [38]

Answer:

The answer is 157

Step-by-step explanation:

4 0
3 years ago
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