Question

Help please!!! Find the point in the first quadrant where the line y=4x intersects a circle of radius 4 centered at the origin.

Answer 1

Answer:

Step-by-step explanation:

X^2+Y^2=16

X^2+4X^2=16

5X^2=16

X^2=16/5

X=+- SQRT(16/5)

X=+- 4SQRT(5)

DISREGARD THE -4SQRT(5) BECAUSE WE ARE DEALING WITH THE FIRST QUADRANT

Answer 2

Answer:

the point is : (1 ; 4 )

Step-by-step explanation:

an equation for this circle is : x²+y² = 16

you have the system : x²+y² = 16 ....(1)

                                      y = 4x .....(2)

Substitute y = 4x into (1) and solve for x :

x² + (4x)² = 16

x² +16x² = 16

17x² = 16

x² = 16/17

x = 4/√17   or x = - 4/√17 ( refused) because the point in the first quadrant where  : x ≥0

 x = 4/√17 ≅ 0.970

exact values or give decimal values accurate to at least 3 decimal places

is : x =1

Substitute  x = 1 into (2) : y =4    the point is : (1 ; 4 )