All categories

3 years ago

Help please!!! Find the point in the first quadrant where the line y=4x intersects a circle of radius 4 centered at the origin.

Mathematics

2 answers:

lianna [129]3 years ago

8 0

Answer:

Step-by-step explanation:

X^2+Y^2=16

X^2+4X^2=16

5X^2=16

X^2=16/5

X=+- SQRT(16/5)

X=+- 4SQRT(5)

DISREGARD THE -4SQRT(5) BECAUSE WE ARE DEALING WITH THE FIRST QUADRANT

Firdavs [7]3 years ago

6 0

Answer:

the point is : (1 ; 4 )

Step-by-step explanation:

an equation for this circle is : x²+y² = 16

you have the system : x²+y² = 16 ....(1)

y = 4x .....(2)

Substitute y = 4x into (1) and solve for x :

x² + (4x)² = 16

x² +16x² = 16

17x² = 16

x² = 16/17

x = 4/√17 or x = - 4/√17 ( refused) because the point in the first quadrant where : x ≥0

x = 4/√17 ≅ 0.970

exact values or give decimal values accurate to at least 3 decimal places

is : x =1

Substitute x = 1 into (2) : y =4 the point is : (1 ; 4 )

You might be interested in

(25 POINTS) Terry realized that 25% of his money was $12.50. He made a double number line to represent this. What number would g

DedPeter [7]

Answer:

you would double it A 0 12.50 25.00

B 0 25 50

Step-by-step explanation:

not 100% hope > helped

7 0

3 years ago

Sam is moving into a new apartment. Before he moves in, rhe landlord asks that he pay the first months rent and a securit deposi

Archy [21]

so u need to divide 1.5 by 3275

5 0

4 years ago

A boat traveled 147 miles downstream and back. The trip downstream took 7 hours. The trip back took 21 hours. What is the speed

zimovet [89]

Answer:

The speed of current is 7 miles per hour

Step-by-step explanation:

Given as :

The distance cover by boat in downstream = D = 147 miles

The distance cover by boat in upstream = d = 147 miles

The time taken in downstream trip = T = 7 hours

The time taken in upstream trip = t = 21 hours

Let The speed of boat in still water = x mi/h

And The speed of current = y mi/h

The speed in downstream = S = (x + y) mi/h

The speed in upstream = s = (x - y) mi/h

Now, According to question

∵ Distance = speed × time

For downstream

D = S × T

Or, 147 miles = (x + y) mi/h × 7 hours

i.e 7 (x + y) = 147

Or, x + y = $\dfrac{147}{7}$

∴ x + y = 21 ........A

For upstream

d = s × t

Or, 147 miles = (x - y) mi/h × 21 hours

i.e 21 (x - y) = 147

Or, x - y = $\dfrac{147}{21}$

∴ x - y = 7 .......B

Now, Solving equations A and B

So, (x + y) + (x - y) = 21 + 7

Or, (x + x) + (y - y) = 28

Or, 2 x + 0 = 28

∴ x = $\dfrac{28}{2}$

i.e x = 14 miles per hour

The speed of boat in still water = x = 14 mi/h

Now, putting the value of x into eq B

So, y = x - 7

Or, y = 14 - 7

i.e y = 7 miles per hour

The speed of current = y = 7 mi/h

Hence, The speed of current is 7 miles per hour . Answer

7 0

3 years ago

Can u guys PLEASE ANSWER this question 2 ASAP

kicyunya [14]

Answer:

Sorry but where's the question

Step-by-step explanation:

6 0

3 years ago

What is the equation of the line that passes through 1,2 and is parallel to the line whose equation is 2x + y - 1 = 0

melamori03 [73]

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1) you have : x_1 =1 and y_1 =2

m the slope m= -2 (same slope for the line : 2x+y-1=0 because this lines are parallel and you can write y=-2x-1

an equation for this line is : y-2 = -2(x-1)

7 0

4 years ago