Answer:
The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given sample size 'n' =200
given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school
sample proportion

The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Standard deviation of the proportion

10x0 one time. But it technically should be zero times.
Answer:2/19
Step-by-step explanation:
Answer:
The answer is A!
Step-by-step explanation:
Its correct, I took the quiz :)
Answer:
x=18
pq=101
qr=101
pr=202
Step-by-step explanation:
6x-7=5x+11
+5x pasa a restar como -5x al primer miembro y -7 pasa como +7x al segundo miembro y la ecuacion quedaria asi:
6x-5x=11+7
6x-5x=x
11+7=18
entonces x=18
pq=6x-7
pq=6(18)-7
pq=108-7
pq=101
y como se sabe que pq=qr porque hay un punto medio y dos segmentos cuando los divide un punto medio esos dos segmento miden igual entonces
por eso pq=qr
y como pq=101 qr=101
por ultimo
pr=pq+qr
pr=101+101
pr=202