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zloy xaker [14]
3 years ago
13

What is the gcf of 3x^2 and 7y

Mathematics
1 answer:
Svetach [21]3 years ago
7 0
Answer :
<span>Unless we have a relationship defined between x and y there is no common factor apart from 1.
</span>
hope it helps 
~Reema
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The ratio of two computers is 3:2.
serious [3.7K]

Answer:

1. $82,500

2. 169 : 110

Step-by-step explanation:

The computation is shown below:

Given that

1. Ratio between two computers is 3:2

And the first computer cost is $55,000

Let us assume the price of the second computer be x.

As we know that

Product of extremes = Product of mean.

2 : 3 :: 55000 : x .

Now cross mutiplication is to be done

2x = $55,000 × 3

x = $1,650,000 ÷ 2

= $82,500

2. Now if the price of the 2nd computer rised by $2,000

So the new cost would be

= $82,500 + $2,000

= $84,500

Now the ratio would be

= $55,000 :  $84,500

= 169: 110

8 0
3 years ago
I need help with these two questions please!!!please HeLp mE
Hatshy [7]

Answer:

5, 2, 1, 2, 3

Step-by-step explanation:

5 0
3 years ago
Please help with this
irakobra [83]

Answer:

1

Step-by-step explanation:

because we have to fine p *b

7 0
2 years ago
Evalute costheta if sintheta = (sqrt5)/3
torisob [31]

Answer:

\large\boxed{\cos\theta=\pm\dfrac{2}{3}}

Step-by-step explanation:

Use \sin^2x+\cos^2x=1.

We have

\sin\theta=\dfrac{\sqrt5}{3}

Substitute:

\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}

3 0
3 years ago
Read 2 more answers
455 cm converted to mL
Tom [10]
455 cubic centimeters =
455 milliliters
8 0
2 years ago
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