Option B: ![$y=-\sqrt[3]{x-4}+7$](https://tex.z-dn.net/?f=%24y%3D-%5Csqrt%5B3%5D%7Bx-4%7D%2B7%24)
is the new equation
Explanation:
The given equation is ![$y=-\sqrt[3]{x}$](https://tex.z-dn.net/?f=%24y%3D-%5Csqrt%5B3%5D%7Bx%7D%24)
We need to find the new graph which is shifted 7 units up and 4 units right.
First, we shall shift the graph 7 units up.
The general formula to shift the graph b units up is given by
Thus, to shift the graph 7 units up, let us substitute 
and ![f(x)=-\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D)
in the general formula, we have,
![y=$-\sqrt[3]{x}$+7](https://tex.z-dn.net/?f=y%3D%24-%5Csqrt%5B3%5D%7Bx%7D%24%2B7)
Now, we shall shift the graph 4 units right.
The general formula to shift the graph b units right is given by
Thus, to shift the graph 4 units right, let us substitute 
and ![f(x)=$-\sqrt[3]{x}+7$](https://tex.z-dn.net/?f=f%28x%29%3D%24-%5Csqrt%5B3%5D%7Bx%7D%2B7%24)
in the above equation, we have,
Therefore, the new equation is
Therefore, Option B is the correct answer.
Answer:
You are given two points, (0,6) and (3,-3), so use the two-point formula for the equation of a line:
y - y1 = ( (y2 - y1) / (x2 - x1) ) (x - x1)
y - 6 = ( -9 / 3 ) (x - 0)
y - 6 = -3x
y = -3x + 6 This is: y = mx+b
Step-by-step explanation:
hope this will help you..
Answer:40
Step-by-step explanation:
On a fair die, each face has a 1/6 chance of landing on each toss.
5 and 6 are the only faces greater than 4, therefore there is a 1/6 + 1/6 = 2/6 chance of the die landing on a number greater than 4 for each toss.
Multiply the probability by the total number of tosses to get the number of tosses that are greater than 4.
120 * (2/6) = 240/6 = 40
Approximately 40 tosses will land on a number greater than 4.
Answer:
I hate math too <3
Increasing: [0,1]
Decreasing: (infinity,0] U [1,infinity)
Answer is
−7 ≤ x ≤ 4
Step-by-step explanation:
