Question

7. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7, find the smallest possible value of m. (3 marks)
​

Answer 1

Answer:

187

Step-by-step explanation:

Least common multiple:

To find the required number,

1. Find the LCM of 30 , 36  and 45
2. Then add 7 to the LCM

30 =  2 * 3 * 5

36 = 2 * 2 * 3 * 3 = 2² * 3²

45 = 2 * 3 * 3 = 2 *3²

LCM = 2² * 3² * 5

        = 4 * 9 * 5

        = 180

Required number = 180 + 7

                             = 187