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matrenka [14]
3 years ago
6

What is a rule to find the number of non overlapping triangles in a polygon

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0
Give a algebraic expression for the number of non overlapping triangles in a polygon that has "n" sides
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Does 8 + 2(x−6) = −2 + 2x −2 have one solution, no solutions, or infinite solutions.
tia_tia [17]

Answer:

Infinite solutions

Step-by-step explanation:

All solutions are possible.

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What is the square route of 6,897?
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Answer: 11 square root 57

Step-by-step explanation:

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Look at the figures. How can you prove these triangles are congruent?
Novosadov [1.4K]

Answer:

A. \Delta ABC\cong \Delta DEF by the SAS postulate.

Step-by-step explanation:

We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.

We can see that side DF of triangle DEF is equal to side AC of triangle ABC.

We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.

The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.

Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.

5 0
3 years ago
What is 49% of 15?<br> Is it 1.5,4,7.5,or 9?
Semmy [17]
49\% \ of \ 15  \\ \\  \frac{49}{100} \cdot15= \frac{735}{100}=\boxed{\boxed{7.5  }}
4 0
3 years ago
Alyze the following special produ
Eddi Din [679]

Answer:

1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) Solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) Solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26

So, solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: (a+b)^2=a^2+2ab+b^2

Solving:

(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: (a-b)^2=a^2-2ab+b^2

Solving:

(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

5 0
2 years ago
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