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marshall27 [118]
3 years ago
7

Which of the following could be the ratio between the lengths of the two legs

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0
30:60:90
3:6:9
1:2:3
I can’t make sense of given answers
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Alexeev081 [22]
28°
Since KL and FG are perpendicular they create a 90° angle. 180-90-62=28
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What is the value of x in the regular polygon?<br> The value of x is?
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Step-by-step explanation:

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2 to the 3rd power times 5 to the 2nd power
nirvana33 [79]

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An 8-sided die is rolled. Find the probability of rolling a 1 or even number
leonid [27]

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4 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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