D 100% corect took my test $$$$$$$$$$$$$$
We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2
y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3
the coordinates of the focus are (2,3)
First 1/5 is equivalent to 20% so to get 20% of both of them multiply by .2. so 400×.2=80 and 90×.2=18
Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
