Answer:
z=12500
Step-by-step explanation:
Of means multiply and is means equals
85% *z = 106250
Change to decimal form
.85z = 106250
Divide each side by .85
.85z/.85 = 106250 /.85
z=12500
Answer:C
Step-by-step explanation:
Answer:
x=+/-3
Step-by-step explanation:
x^4-5x^2-36=0
factor
(x^2-9)(x^2+4)=0
split into 2 equations because one of these terms will need to equal zero for the eqation to be true
x^2-9=0 x^2+4=0
x^2=9 x^2=-4
x=+/-3 no real numbers
(a) The lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
(b) The lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
(c) The lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
<h3>
Lateral surface area of the prism</h3>
L.S.A = Ph
where;
- P is perimeter of the base
- h is height of the prism
h² = 17² - 8²
h² = 225
h = 15
L.S.A = (3 x 16) x 15 = 720 sq units
<h3>Total s
urface area of the prism</h3>
T.S.A = PH + 2B
T.S.A = 720 + 2(16) = 752 sq units
<h3>
Lateral surface area of the cone</h3>
L.S.A = πrt
where;
- t is the slant height = 17
r² = 17² - 15²
r² = 64
r = 8
L.S.A = π(8)(17) = 136π sq units
<h3>
Total surface area of the cone</h3>
T.S.A = πrt + πr²
T.S.A = 136π sq units + π(8)²
T.S.A = 200π sq units
<h3>
Lateral surface area of the cylinder</h3>
L.S.A = 2πrh
where;
- r is the radius of the cylinder = 11
- h is height of the cylinder = 11
L.S.A = 2π(11 x 11) = 242π sq units
<h3>Total
surface area of the cylinder</h3>
T.S.A = 2πrh + 2πr² = 2πr(r + h)
T.S.A = 2π(11)(11 + 11)
T.S.A = 484π sq units.
Thus, the lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
- the lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
- the lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
Learn more about surface area here: brainly.com/question/76387
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Answer:
I am not sure...it's either option 3 or 4....
go with option 4
