Question

Please help me solve this

Answer 1

Answer:

$\frac{1}{2^{7}} \frac{1}{\sqrt{e}}$

Step-by-step explanation:

After derive a couple of times you  can see

$f^{n}(x) = \frac{-1^{n+1}}{2^{n}} e^{\frac{-x}{2}}$

Replacing n by 7 and x by 1 we get

$f^{7}(1) = \frac{-1^{7+1}}{2^{7}} e^{\frac{-1}{2}} = \frac{1}{2^{7}} \frac{1}{\sqrt{e}}$