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3 years ago

6

Drag expressions to complete each equation.

2 answers:

Sphinxa [80]3 years ago

6 0

Answer:

a^-b = 1/a^b

a^b/a^c = a^b-c

a^c/b^c = (a/b)^2

Step-by-step explanation:

Ainat [17]3 years ago

3 0

A^-b is the same as 1/a^b.

When there is a negative power, place the number and power over 1.

a^b/a^c = a^(b-c).

c is a negative power, because it is being divided, and is underneath b, which is a positive (and so it stays in the numerator).

a^c/b^c = (a/b)^c

Inside this one, the power of c is distributed to all numbers inside the parenthesis, in this case a and b.

hope this helps

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No, since 0 doesn't belong to the domain.

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3 years ago

Read 2 more answers

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

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Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

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3 years ago