Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
The coordinates to the second spot can be represented by the coordinates
(-12 + 3, 8 -11)
Since we are going 3 yards to the east we would be affecting the x-axis and since we are going east we will need to add 3 yards the x axis of the first spot
11 yards south would be affecting the y- axis negatively. We would need to subtract 11 from the y- axis of the first spot.
the coordinates of the second spot would be
-12 +3 = -9
8 -11 = -3
(-9, -3)
2 is in the hundred thousands place
There is no picture but ok
