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aliina [53]
3 years ago
9

What are the solutions to 2x - y = 16 and 8y = 4(4x - 32)

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

2x-y=16

8y=4(4x-32)

------------------

y=2x-16

8(2x-16)=16x-128

16x-128=16x-128

infinitely many solutions

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Claudia studied for 45 minutes. Crystal studied for 5 minutes.
andreev551 [17]

Answer:

The number of minutes Claudia studied is <u>9</u> times as many minutes that Crystal studied.

Step-by-step explanation:

45/5=9

8 0
2 years ago
A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

6 0
3 years ago
Do all 4 pls hahahahahhahahahahaha
riadik2000 [5.3K]
1.-4
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5 0
3 years ago
Does secondhand smoke affect asthma?
coldgirl [10]
This is an non linear graph because it doesn’t show a straight line
5 0
3 years ago
maria has a ribbon that is 5/8 yard long if she cuts her ribbon into 6 pieces of equal length what will be the length in yards o
lozanna [386]

Answer:

(5/8) / 6

(5/8) * (1/6) = 5/48 yard

4 0
3 years ago
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