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xxMikexx [17]
3 years ago
9

What is 9-10+25÷5+(-2)

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

-3.5

Step-by-step explanation:

9-10+25÷5(-2)

=9-10+25÷(-10)

=9-10+(-2.5)

=-1+(-2.5)

=-3.5

Rashid [163]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Simplify using PEMDAS

(first divide 25/5 then add the rest up)

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if an amount of $5,000 is deposited into a savings account at an annual interest rate of 5%, compounded monthly, what is the val
Ugo [173]

Answer:

$8,240

Step-by-step explanation:

We are given that,

Principle amount in the savings account, P = $5,000.

Rate of interest, r = 5% = 0.05

Time period, t = 10

Also, the interest is compounded monthly, n = 12

As, we now that the value of the investment is given by P(1+\frac{r}{n})^{nt}

Thus, we have,

Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

i.e. Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

i.e. Investment Value = 5000(1+0.00417)^{120}

i.e. Investment Value = 5000\times 1.648

i.e. Investment Value = $8,240

Hence, the investment amount after 10 years is $8,240.

5 0
3 years ago
What is the difference between 1/2 and 1 whole?
Travka [436]
1/2 is half of a whole

whole= 1/1. 2/2, 3/3, 4/4 and so on

1/2 are numbers that can be simplify to halves= 1/2, 2/4, 3/6, 4/8, 5/10 and 1/2 are half of the denominator
4 0
3 years ago
Read 2 more answers
Do you guys know the angle?
Paha777 [63]
90 degrees :).........
6 0
3 years ago
Which is the angle of depression from b to c
matrenka [14]

<2

Step-by-step explanation:

that the answer. because it below par

8 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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