Answer:
Slope Intercept Form is y = mx +b
1. y = x + 8
2. y = 1/2x + -5
3. y = x + 7
It should be D but I might be wrong. Please tell me if I am. Hav a good day!
Answer:
y=x+2 will be a positive upwards graph that has a slope of 1 this means it will cross diagonally perfectly it won't change directions and it won't go up more than down or left more than right. It will cross the x axis at 2.
y=-x+2 It will be the same thing but this time starts from the top left and goes down gets to x axis at positive 2 again
y=|x|+2 This will go down from top left again and hit positive 2 on y axis then go back up making a v it does not curve and it does have a perfect slope of 1 making it easy to graph.
Step-by-step explanation:
I believe the answer is “If none of the input values are repeated, the relation is a function” because one input must have one output.
Answer:
B 1
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called Synthetic Division. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
2| -2 1 5 0 4 1
↓ -4 -6 -2 -4 0
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-2 -3 -1 -2 0 1→ -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [-2x⁵ + x⁴ + 5x³ + 4x + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is, tells you whether the next step is to <em>subtract</em> or <em>add</em>, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that -2 in your quotient can be a -2x⁴, and the -3 [x³] follows right behind it, then 1 [-x²], -2[x], and finally, [1\x - 2] (remainder is 1, so set it over your denominator, which is the divisor), giving you the other factor of -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹.
I am joyous to assist you anytime.
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