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3 years ago

How is an electromagnet different from a bar magnet?

Physics

2 answers:

Umnica [9.8K]3 years ago

6 0

Answer:

The answer should be C

Explanation:

The reason for that is because electromagnet needs electricity to start attracting anything at all but it's attracting power is also stronger because of it

Warning: This may or may not be a completely correct answer, hope you compare answer and don't blindly trust my answer

Phoenix [80]3 years ago

6 0

Answer:

it's c. I did the test

Explanation:

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The motion of as car is drawn is vi against th graph

LenKa [72]

10 and 40 would be your answer i believe.

3 0

3 years ago

Where is the density of the material greater, at point B or point C?<br> Explain why.

DerKrebs [107]

Answer: The density is greater at point C

Explanation: At that point

The convention current slowly cools off

8 0

4 years ago

Water is flowing through a channel that is 12m wide with a

Alexus [3.1K]

Answer:

Velocity from second channel will be 1.6875 m/sec

Explanation:

We have given width of the channel , that is diameter of the channel 1 $d_1$ = 12 m

So radius $r_1=\frac{d_1}{2}=\frac{12}{2}=6m$

Speed through the channel 1 $v_1=0.75m/sec$

Width , that is diameter of the channel 2 $d_2=4m$

So $r_2=2m$

From continuity equation

$A_1v_1=A_2v_2$

$\pi \times 12^2\times 0.75=4\times \pi\times 4^2\times v_2$

$v_2=1.6875m/sec$

So velocity from smaller channel will be 1.6875 m /sec

6 0

3 years ago

A tetrameric protein dissociates into dimers when the detergent sodium dodecyl sulfate (SDS) is added to a solution of the prote

KatRina [158]

Answer:

At the dimer-dimer interface there might be acting non-covalent forces (van der waals, Hidrogene bridges, hydrophobic forces)

At the monomer-monomer interface there might be covalent forces acting (disulfide bridges).

Explanation:

On the SDS-PAGE application works by disrupting non-covalent bonds in the proteins, and so denaturing them. Therefore, the disulfide bridges won´t be disrupted, so the monomers will remain bounded.

5 0

4 years ago

What’s the resistance in the circuit

inna [77]

Answer:

I = 0.75 A

Explanation:

The question is not to calculate the resistance, but to calculate the current. (The resistance is already given by the value of 2 Ohm).

U = I * R

I = U / R

with U = 1.5 V and R = 2 Ohm

I = 1.5 / 2

I = 0.75 A

3 0

3 years ago