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olchik [2.2K]
3 years ago
14

Suppose two equal mass cars traveling with equal speeds in opposite directions inelasticcollide head on and stick together. What

fraction of the energy is dissipated
Physics
1 answer:
Annette [7]3 years ago
5 0

A collision which is inelastic is one in which the internal energy changes.

All the kinetic energy is dissipated

Reasons:

The given parameters are;

The mass of one car = The mass of the second car in the collision = m

The type of collision = Inelastic collision

The speed of each of the cars in the collision = v and -v

Solution:

In an inelastic collision, we have;

m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = (m_1 + m_2) \cdot v_f

Therefore, we get;

m \cdot v_{i} -m \cdot v_{i} = 0= 2 \cdot m \cdot v_f

Which gives;

v_f = 0

The collision is an example of a perfectly inelastic collision, and the final velocity after the collision is zero.

The change in the energy is \Delta K.E. = K.E._{final} - K.E._{initial}

K.E._{initial} = 0.5·m·v² + 0.5·m·v² = m·v²

ΔK.E. = 0.5·(2·m)×0 - 0.5·m·v² + 0.5·m·v² = -m·v²

ΔK.E. = -m·v²

The negative sign stands for energy given out, which gives;

The energy dissipated = m·v² (The total initial kinetic energy)

Therefore, <u>all the kinetic energy is dissipated</u>

Learn more here:

brainly.com/question/19106769

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Kamila [148]

Answer:

(a) \frac{m}{s^2}

(b) \frac{m}{s^3}

(c) 1 s

(d) 20 m

(e) 1 m

(f) 0\frac{m}{s}

(g) -12\frac{m}{s}

(h) -36\frac{m}{s}

(i) -72\frac{m}{s}

(j) -6\frac{m}{s^2}

(k) -18\frac{m}{s^2}

(l) -30\frac{m}{s^2}

(m) -42\frac{m}{s^2}

Explanation:

Since <em>x</em> is measured in meters and <em>t</em> in seconds, constants <em>a </em>and <em>b</em> must have units that gives meters when multiplied by square and cubic seconds respectivly, so that would mean \frac{m}{s^2} for <em>a </em>and \frac{m}{s^3} for <em>b</em>.

We can get the velocity <em>v </em>equation by deriving the position with respect to <em>t</em>, which gives:

v=6*t-6*t^2

And the acceleration <em>a</em> equation by deriving again:

a=6-12*t

Now for getting the maximun position between 0 and 4, we must find to points where the positions first derivate is equal to cero and evaluate those points. That is <em>v=0</em>, which gives

6*t-6*t^2=0\\6t*(1-t)=0\\t=0 or t=1

For <em>t = 0</em>,<em> x = 0</em> so the maximun position is archieved at 1 second, which gives <em>x = 1 meter</em>.

For obtaining it's displacement <em>r</em>, we can integrate the velocity from 0 seconds to 4 seconds, which gives the mean value of the position in that interval:

r=\frac{1}{4}*(2*4^3-3*4^2)m\\r= 20m

For the remaining questions, we just replace the values of <em>t</em> on the respective equations.

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3 years ago
A rock resting high in a cliff is an example of an object with what type of energy?
Basile [38]
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8 0
4 years ago
Read 2 more answers
In California the pacific plate slides past the North American plate. If the pacific plate is moving at a speed of 5 centimeters
RUDIKE [14]

Answer:

2000years

Explanation:

We will either convert the distance to centimeters or speed to meters/second.

Converting distance to centimeters: 100 meters= 100*100centimeters =10000centimeters.

time=distance/speed

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5 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!!!​
Zina [86]

Answer:

x₁ = 58.09 m

Explanation:

Displacement is calculated by finding the final distance away from a point then subtracting the initial distance.

Given that initial position of object is x=25.89 m

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Final position x₁=?

Δx = x₁-x

32.2= x₁-25.89

32.2+25.89 = x₁

58.09 m =x₁

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3 years ago
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