On a distance vs. time graph of an object's motion, distance is usually
1 answer:
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The velocity of B after elastic collision is 3.45m/s
This type of collision is an elastic collision and we can use a formula to solve this problem.
<h3>Elastic Collision</h3>The data given are;
- m1 = 281kg
- u1 = 2.82m/s
- m2 = 209kg
- u2 = -1.72m/s
- v1 = ?
Let's substitute the values into the equation.
From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.
Learn more about elastic collision here;
Answer:
See explanation below
Explanation:
If we are talking about the kinetic energy of the cylinder of oxygen:
The kinetic energy possessed by any object is given by
where
m is the mass of the object
v is its speed
In this case, we have one cylinder carried by a car and one standing on a platform: this means that the speed of the cylinder carried by the car will be different from zero (and so also its kinetic energy will be different from zer), while the speed of the cylinder standing on the platform will be zero (and so its kinetic energy also zero). Therefore, the kinetic energy of the cylinder carried by the car will be larger than that standing on a platform.
Instead, if we are talking about the kinetic energy due to the random motion of the molecules of oxygen inside the cylinder:
The kinetic energy of the molecules in a gas is directly proportional to the absolute temperature of the gas:
where k is called Boltzmann constant and T is the absolute temperature of the gas. Therefore, we see that K does not depend on whether the gas is in motion or not, but only on its temperature - therefore, in this case there is no difference between the kinetic energy of the cylinder carried by the car and that standing on the platform (assuming they are at the same temperature)