Ask question

Ask question

All categories

3 years ago

9

the giant swallowtail is the largest butterfly in the united states . its wingspan can be as large as 16 centimeters. what is th

e maximum wingspan in millimeters?

2 answers:

s2008m [1.1K]3 years ago

5 0

160 : You Are Converting Centimeters To Millimeters So Multiply By 100.
Hope This Helps! :)

Anna11 [10]3 years ago

4 0

The maximum wingspan in millimeters would be 160.

The prefixes, Kilo, Hecto, Deca, Deci, Centi, and Milli all increase by powers of ten. An easy way to remember this is

King Kilo
Henry Hecto
Died Deca
Drinking Deci
Chocolate Centi
Milk Milli

Since Centi is greater than Milli by one space, you increase by ten, which means you move the decimal once to the right.

Hope this helps! :)

You might be interested in

80 points! Look at pic attached. I will mark brainiest if you explain your reasoning good. Random answers will be reported.

gregori [183]

Answer: No, your friend is not correct. You cannot use a similarity transformation to turn a square into a rectangle. Here's why:

1) If you used a similarity transformation, the size and position of the shape would change, but the shape itself remains the same.

2) Squares and rectangles are NOT similar.* Referring to the first point I listed, if the shapes are not similar, then a similarity transformation cannot be used to turn one shape into another.

<em>*Similar means that the edges are proportional to one another, such as a square with sides of 4 meters vs a square with sides of 2 meters: the sides are different lengths, but the shape is the same.</em>

I hope this helps! Please feel free to comment below if you need any clarification. Have a good day, and good luck on your assignment. :)

7 0

3 years ago

Please please help me on this question

Delvig [45]

-7x^2 - 6x^2 + 3x + 5x - 5 + 2
-13x^2 + 8x - 3

5 0

3 years ago

Which is greater, 0.28 or 0.205? Explain how you know.

LuckyWell [14K]

Answer:

Step-by-step explanation:

0.28 is roughly the same as 0.280, which has 3 significant digits (same as 0.205 has 3 significant digits). It's easier when we compare numbers having the same number of decimal places.

Comparing 0.280 to 0.205, we see that the hundredths place of 0.280 (which is 8) is greater than the hundredths place of 0.205 (which is 0). Thus 0.28 is greateer than 0.205.

6 0

3 years ago

Sarah needs to complete 10,008 hours of guitar practice. How many hours of practice a day should she do to reach her goal in 3 y

avanturin [10]

10008 hours per 3 years is average of 3336 hours per year, or about 9.1 per day.

4 0

3 years ago

Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: $\frac{\cos(x)}{\sin(x)}=\cot(x)$ and $\frac{\sin(x)}{\cos(x)}=\tan(x)$

So we have:

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

I'm going to factor out $\frac{1}{\sin(x)}$ because if I do that I will have the $\csc(x)$ factor I see on the right by the reciprocal identity:

$\csc(x)=\frac{1}{\sin(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show $\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$ is equal to $\csc(\frac{\pi}{2}-x)$ .

So since I want one term I'm going to write as a single fraction first:

$\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$

Find a common denominator which is $\cos(x)$ :

$\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}$

$\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}$

$\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}$

By the Pythagorean Identity $\cos^2(x)+\sin^2(x)=1$ I can rewrite the top as 1:

$\frac{1}{\cos(x)}$

By the quotient identity $\sec(x)=\frac{1}{\cos(x)}$ , I can rewrite this as:

$\sec(x)$

By the cofunction identity $\sec(x)=\csc(x)=(\frac{\pi}{2}-x)$ , we have the second factor of the right hand side:

$\csc(\frac{\pi}{2}-x)$

Let's just do it all together without all the words now:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

7 0

3 years ago