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fiasKO [112]
3 years ago
6

How do algebra tiles help you solve equations?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

Algebra tiles make solving equations, merging like words, or factoring polynomials a visual operation, similar to students using counters to make sense of addition in elementary school, or students using number lines to make sense of integers.

Step-by-step explanation:

i hope this helped

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O que são números racionais
Dmitrij [34]
<span>Números racionales son números que pueden ser wriiten como una proporción, y pueden ser escritos como una fracción también. Un ejemplo de un número racional sería dos cuartos (2/4), medio (1/2), etc.</span>
6 0
4 years ago
The poetry section of the library has 6 bookcases. Each bookcase has 3 shelves. There are 10 books on each shelf. How many total
torisob [31]

Answer: total books = 180

Step-by-step explanation:

Given: Poetry section of the library has 6 bookcases.

Number of shelves in each bookcase = 3

Total shelves =  (Number of shelves in each bookcase) x (Number of bookcases in each poetry section)

= 3 x 6

= 18

Number of books in each shelf = 10

Total books = (number of shelves) x 10

= 18 x 10

= 180

hence, total books in the poetry section= 180

5 0
3 years ago
There is one integer for which there does not exist another integer with the same absolute value, What is that integer?
kotykmax [81]
Zero, it is not negative or positive.
7 0
4 years ago
Read 2 more answers
Alessandro currently has $2,400 in his savings account. He saves $250 per month. Bea currently has $1,750 in her account. She sa
dusya [7]
Bea will have $540 more than Alassandro after 12 months
5 0
4 years ago
Read 2 more answers
What is the first term of the geometric sequence presented in the table below? n 4 9 an 243 59,049
Studentka2010 [4]
Reminder:  the formula for a geom. seq. is

a(n) = a(1)*r^(n-1), where a(1) is the first term, n is the counter and r is the common ratio. 

I first noted that 243 is a power of 3; specifically, 243=3^5, or 243=3(3)^4, or 243=(3^2)(3)^(4-1).  Notice that I'm trying here to rewrite 243=3^5 in the form a(n) = a(1)*r^(n-1):    a(4) = a(1)(3)^(4-1), or a(4) = a(1)(3)^3 = 243.  Then by division we find that a(1) = 243/27 = 9.  Is it possible that a(1)=9?

Let's try out our formula   a(n)=9(3)^(n-1).  Steal n=9 and see whether this formula gives u s 59049:

n(9) = 59049 = 9(3)^(9-1), or  9(3)^8.  True or false?  3^8= 6561, and 9(3)^8 = 59049.

YES!  That's correct.

Therefore, the desired formula is

a(n) = 9(3)^(n-1).  The first term, a(1) is 9(3)^(1-1) = 9(3)^0 = 9*1 = 9.

6 0
4 years ago
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