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morpeh [17]
3 years ago
6

WILL GIVE CROWN..........Area of triangle PQR = 10.2 square units Area of triangle PRS = 11.5 square units Area of triangle PST

= 16.3 square units A polygon PQRST is shown. The vertices P and R are joined with a dashed line, and the vertices P and S are joined with a dashed line. The area of Figure PQRST is ______ square units. (Input whole number only.)
Mathematics
2 answers:
marshall27 [118]3 years ago
7 0
93.725 because you multiply then divide by 2 hope this helps :)
Helen [10]3 years ago
4 0

Answer: 93.725 hope this helps

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answer: mode:40 med:30

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In the circle, m arc BC = 72°. The diagram is not drawn to scale. <br><br>What is m angle BCP
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Answer:

Measure of ∠BCP is 36°

Step-by-step explanation:

Given the circle in which measure of arc BC is 72°

we have to find the measure of angle BCP.

m∠BOC=∠2=72°

By theorem angle subtended at the centre is twice the angle formed at the circumference of circle.

∴ ∠2=2∠1 ⇒ 72=2∠1

⇒    ∠1=36°

By alternate segment theorem which states that

The angle formed between a chord and a tangent through one of the end points of chord is equals to angle in alternate segment.

⇒ ∠3=∠1=36°

Hence, measure of ∠BCP is 36°

Option D is correct

   

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In a random sample of males, it was found that 28 write with their left hands and 210 do not. In a random sample of females, it
Drupady [299]

Answer:

a) Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

b) z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271    

c)p_v =P(Z   

d) If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant lower than the proportion of female that write with their left hand

Step-by-step explanation:

1) Data given and notation  

X_{M}=28 represent the number of men that write with their left hand

X_{W}=62 represent the number of women  that write with their left hand

n_{M}=210+28=238 sample of male selected

n_{W}=62+435=497 sample of female selected

p_{M}=\frac{28}{238}=0.118 represent the proportion of men  that write with their left hand

p_{W}=\frac{62}{497}=0.125 represent the proportion of women that write with their left hand

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the rate of left-handedness among males is less than that among females , the system of hypothesis would be:  

Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{28+62}{238+497}=0.122

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271  

4) Statistical decision

We have a significance level provided \alpha=0.05, and now we can calculate the p value for this test.  

Since is a one left side test the p value would be:  

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.05, 0,1,0.15 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant loer than the proportion of female that write with their left hand .  

6 0
3 years ago
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