Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
The 5 is in the tens spot and the 8 is in the ones.
Look at chart. Plug in an 8 where it says ones, and the 5 where it says tens. Yeah?
Answer: -13, -17, -21
Explanation: Subtract 4 from each term. Do this for 3 terms
The answer this problem is -247
Answer:
the a is c tthinck
Step-by-step explanation:
