1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
UkoKoshka [18]
3 years ago
11

What special identity group is typically used when a user accesses an FTP server that doesn't require user account logon?

Computers and Technology
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

The correct answer to the following question will be "​Anonymous logon".

Explanation:

  • Windows would never let anyone sign in interactively with an anonymous logon to the device, a person who has linked to the device without a login and password being given.
  • So they won't have to verify to an account of the user just whether you are running any shares.r document, let everyone log into the machine collaboratively with such a logon.

Therefore, Anonymous logon is the right answer.

You might be interested in
1. ¿Qué es un cursograma?
erma4kov [3.2K]

Answer:

Un cursograma permite representar gráficamente procedimientos administrativos. Constituyen instrumentos importantes para la visualización global y esquemática del conjunto de tareas administrativas.

6 0
2 years ago
Read 2 more answers
Test if value is not less than 13.6.
svetoff [14.1K]

value = whatever you want

if not value < 13.6:

   print("Value is greater than or equal to 13.6.")

else:

   print("Value is less than 13.6.")

5 0
3 years ago
The excessive use of the internet and the web for personal use at work is sometimes called ____ .
Elodia [21]
This is called Cyberslacking
7 0
3 years ago
Read 2 more answers
CHALLENGE ACTIVITY |
fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0
3 years ago
cellPhoneBill(m,tx)Write the function cellPhoneBill()that takes two int m and txas input and returns a float.The function takes
lidiya [134]

Answer:

The solution code is written in C++

  1. float cellPhone(int m, int tx){
  2.    float COST_PER_MIN = 0.1;
  3.    float COST_PER_MESSAGE = 0.2;
  4.    
  5.    float bill_amount = m * COST_PER_MIN + tx * COST_PER_MESSAGE;
  6.    
  7.    return bill_amount;
  8. }

Explanation:

Firstly, declare a function named cellPhone() that takes two input parameters, m and tx (Line 1).

Since the policy of the carrier company is not given in the question, I make a presumption that the cost per minutes is $0.10 and the cost per message is $0.20 (Line 2- 3).

Next, apply the formula m * COST_PER_MIN + tx * COST_PER_MESSAGE to calculate the total bill (Line 5) and return the bill_amount as function output (Line 7).

4 0
3 years ago
Other questions:
  • Which of the following is a full selector?
    12·1 answer
  • The official record of a high school student's performance is called:
    6·1 answer
  • What are the modes of operation of WLANs?
    5·1 answer
  • Be my friend plzzzzzzz
    7·2 answers
  • Which institution developed outside the limits of the written costitution of the united states ?
    14·1 answer
  • MICR is an input or output devices
    5·1 answer
  • Which of the following is the correct binary representation of the number 2?
    14·1 answer
  • In two to three sentences, describe one advanced search strategy and how it is useful.
    13·1 answer
  • Click here for a answer
    15·1 answer
  • When would instant messaging be the least effective means of communication
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!