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Scorpion4ik [409]
3 years ago
12

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

e-day ticket is $35. For one performance, 40 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1100. What was the price of each kind of ticket?
Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

Advance tickets-$15

Same-day tickets-$20

Step-by-step explanation:

let x be the cost of advance tickets and y cost of same-day tickets:

x+y=35\ \ \ \ \  \ \ ...i

Given that there were 40 advance and 25 same-day tickets for a total of $1100:

40x+25y=1100\\\\8x+5y=220\ \ \ \  \ \ \ \ \ \ \ ...ii

#Make x the subject in i and substitute in ii:

x=35-y\\\\\therefore 8x+5y=220, x=35-y\\\\8(35-y)+5y=220\\\\280-8y+5y=220\\\\60=3y\\\\y=20\\\\x=35-y=35-20=15

Hence, advance tickets cost $15 each while same-day tickets cost $20 each.

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Oksanka [162]

Answer:

  • ≈ 44 km

Step-by-step explanation:

5 miles = 8 km

<u>Then:</u>

  • 1 mile = 8/5 km

<u>Then 27.4 miles is:</u>

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6 0
3 years ago
While sitting on a rooftop 95 feet off the ground Mary flicks a twig up and off of the ledge with the initial vertical velocity
cestrela7 [59]

Answer:

The maximum height of the twig is 96.6 feet off the ground

Step-by-step explanation:

To determine the maximum height of the twig,

First, we will determine the height distance covered by the twig after Mary flicks the twig up.

From the question,

Mary flicks a twig up and off of the ledge with the initial vertical velocity of 10 feet per second, that is

the initial velocity of the twig is 10 feet/second

At maximum height, the final velocity is 0

From on the equations of motions for bodies moving upwards,

v² = u² - 2gh

Where v is the final velocity

u is the initial velocity

g is the acceleration due to gravity (Take g = 9.8m/s² = 32.17 ft/s²)

and h is the height

From the question

u = 10 feet/second

and v = 0 feet/second

Putting the values into the equation

v² = u² - 2gh

0² = 10² - 2(32.17)h

0 = 100 - 64.34h

64.34h = 100

h = 100/64.34

h = 1.6 feet

This is the height distance covered by the twig after Mary flicks it up.

Now, the maximum height of the twig will be the sum of the height of the rooftop from the ground and the height distance covered by the twig.

That is,

Maximum height = 95 feet + 1.6 feet

Maximum height = 96.6 feet

Hence, the maximum height of the twig is 96.6 feet off the ground.

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Graph y = | x | + 5
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Step-by-step explanation:

6 0
3 years ago
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