Question

Help please i really really really need it.....

Answer 1

A)

s = sweater

j = jeans

Equations:

4s + 2j = 140

2s + 3j = 150

B)

4s + 2j = 140

2s + 3j = 150

Multiply (-2) to the second equation

-2 (2s + 3j = 150)

-4s - 6j = -300

Now you have the equations:

4s + 2j = 140

-4s - 6j = -300

-----------------------------add

-4j = -160

  j = 40

4s + 2(40) = 140

4s + 80 = 140

4s = 60

 s = 15

The cost for a sweater is $15 and the cost for a jean is $40

We used the elimination method to solve the system of equations.

C)

Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85

Total cost for 1 pair of jeans and 3 sweaters = $85

If she has $225 the

$225 / $85 = 2.64

2 jeans = 2 x 40 = $80

6 sweaters = 6 x $15 = $90

So She can only buy 2 jeans and 6 sweaters