Flammability
the others don't have to do with the chemical composition of an object. (density and color have to do with the physical properties of a substance.)'
hope that I helped :)
Answer:
CuCo3+CaSo4
Explanation:
when they react they form that compound in the reaction called <em>double displacement</em><em>.</em>
0.590 mol of calcium carbonate are in 63.8 g of calcium carbonate.
<u>Explanation:</u>
Chemical substances are framed with respect of their molar quantity, as these are molar ratios, not mass, that occur in stoichiometrically balanced equations. We divide mass by the molar mass of a single molecule or unit of formula to extract moles from mass.
In order to start calculation, firstly the molar mass of calcium carbonate is needed to be detected as follows:
The molar mass of calcium = 40.08 g/mol, carbon is = 12.01 g/mol while for oxygen = 16.00 g/mol.
Thus adding above quantities to calculate molar mass of calcium carbonate: 40.08 + 12.01 + 3(16.00) = 108.09 g/mol.
Now by dividing the mass of calcium carbonate to its molar mass:
63.8g / 108.09 g/mol = 0.590 mol of calcium carbonate.
Answer: The concentartion of solution will be 0.224 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= moles of solute =
= volume of solution in ml = 275 ml
Now put all the given values in the formula of molarity, we get
Therefore, the concentration of solution will be 0.224 M