Answer:
57.2 g
Explanation:
First we <u>convert 66.4 grams of Ba(ClO₄)₂·3H₂O into moles</u>, using its <em>molar mass</em>:
- Molar mass of Ba(ClO₄)₂·3H₂O = Molar mass of Ba(ClO₄)₂ + (Molar Mass of H₂O)*3
- Molar mass of Ba(ClO₄)₂·3H₂O = 390.23 g/mol
- 66.4 g ÷ 390.23 g/mol = 0.170 mol Ba(ClO₄)₂·3H₂O
0.170 moles of Ba(ClO₄)₂·3H₂O would produce 0.170 moles of 0.170 moles of Ba(ClO₄)₂. Meaning we now <u>convert 0.170 moles of Ba(ClO₄)₂ into grams,</u> using the molar mass of Ba(ClO₄)₂:
- 0.170 mol * 336.23 g/mol = 57.2 g
Answer:
D. 0.4 (mol/L)/S
Explanation:
You simply have to plug in the given values into the rate law.
Rate = k[A][B]
Rate = (0.1)(1)²(2)²
Rate = (0.1)(1)²(4)²
Rate = 0.4
One mole of a substance contains 6.02×10∧23 particles,
1 mole of a aluminium contains 27 g
35 g of aluminium contains 35/27 =1.296 moles
Thus, the number of particles will be 1.296 × 6.02 ×10∧23
= 7.804 × 10∧23 particles,
Hence, 35 g of Aluminium contains 7.804 × 10∧23 atoms
Bonding electrons are involved in chemical bonding these electrons have their valnce shell incomplete
