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VikaD [51]
2 years ago
7

If element A is in Group 13 and element B is in Group 17, which ions will be formed when A and B react together?

Chemistry
1 answer:
Kobotan [32]2 years ago
8 0

Answer:

A3+ and B-

Explanation:

Elements in group 13 have outermost electron configuration, ns2np1 hence they form trivalent positive ions.

Elements in group 17 have outermost electron configuration ns2np5 hence they form univalent negative ions.

This implies that, if element A is in Group 13 and element B is in Group 17, the ions formed are A3+ and B-.

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ribosome

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In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe
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We know the law of conservation of mass

  • It states that mass is neither formed nor destroyed in any chemical reaction.
  • Mass of reactants=Mass of products.

Here

  • Mg and I_2 are reactants
  • MgI_2 is product with some yield.
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Lets find the percentage

\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100

\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100

\\ \tt\hookrightarrow 0.23028(010)=23.028\%

6 0
2 years ago
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Roman55 [17]

Answer:

Classifying stars according to their spectrum is a very powerful way to begin to understand how they work.  As we said last time, the spectral sequence O, B, A, F, G, K, M is a temperature sequence, with the hottest stars being of type O (surface temperatures 30,000-40,000 K), and the coolest stars being of type M (surface temperatures around 3,000 K).  Because hot stars are blue, and cool stars are red, the temperature sequence is also a color sequence.  It is sometimes helpful, though, to classify objects according to two different properties.  Let's say we try to classify stars according to their apparent brightness, also.  We could make a plot with color on one axis, and apparent brightness on the other axis, like this:

Explanation:

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diamong [38]

Answer:

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What are the spectator ions in this reaction
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