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VikaD [51]
3 years ago
7

If element A is in Group 13 and element B is in Group 17, which ions will be formed when A and B react together?

Chemistry
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

A3+ and B-

Explanation:

Elements in group 13 have outermost electron configuration, ns2np1 hence they form trivalent positive ions.

Elements in group 17 have outermost electron configuration ns2np5 hence they form univalent negative ions.

This implies that, if element A is in Group 13 and element B is in Group 17, the ions formed are A3+ and B-.

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Using a chemical equation to find moles of product from moles...
kaheart [24]

Answer: 0.600 moles

Balanced eqn for decomposition of the rocket fuel:

2 NH4ClO4 (s) ----> N2 (g) + Cl2 (g) + 2 O2 (g) + 4 H2O (g)

Since, 2 moles of NH4ClO4 produces 2 moles of O2 gas, this means that 0.6 moles of NH4ClO4 will produce 0.6 moles of O2 gas

7 0
2 years ago
6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture
Sladkaya [172]

Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

  • Moles of Na is 6.0 moles
  • Moles of Cl₂ is 4.0 moles

From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

                      = 6.0 moles

Thus, moles of sodium chloride produced is 6.0 moles

3 0
3 years ago
Mike mixes two chemicals in a container. The container quickly becomes
Vedmedyk [2.9K]

Answer:

it is an exothermic reaction

7 0
3 years ago
Select the substance that is thought to be partially responsible for depleting the concentration of ozone in the stratosphere. s
gogolik [260]

Answer:

cfcl3

Explanation:

When the cfcl3 in the atmosphere is hit by UV rays from the sun, it decomposes to Cl atoms. These Cl atoms then react with the ozone producing O2 and ClO. The ClO bombard with O atoms splitting the ClO up and the free Cl atom again bonds to another O3 molecule hence reducing it. One ClO can reduce several O3 molecules (up to 100,000) creating an ozone hole.

2Cl + O3 → 2ClO + 2O2

2ClO + 2O → 2Cl + 2O2

6 0
3 years ago
Which root word of the binary ionic compound ends with -ide
kondor19780726 [428]

Answer: C. The non metal

Explanation:-

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The nomenclature of ionic compounds is given by:

1. Positive ion or metal is written first.

2. The negative ion or non metal is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

For example: CsBr , cesium is metal having an oxidation state of +1 called as Cs^{+} cation and bromine Br^{-} is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr called as cesium bromide.

4 0
3 years ago
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