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4 years ago

What are the elements of PCl5 and the name

Chemistry

1 answer:

prisoha [69]4 years ago

8 0

Phosphorus, Chlorine. The IUPAC name is Phosphorus pentachloride

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The distinctive symbol used to identify radioactive materials is the:

Finger [1]

Tri-blade radiation symbol

4 0

3 years ago

Determine the acid dissociation constant for a 0.010 M nitrous acid (HNO2) solution that has a pH of 2.70. Nitrous acid is a wea

Soloha48 [4]

Answer:

HNO₂ ⇄ H⁺ + NO₂⁻

Ka = 4.0 × 10⁻⁴

Explanation:

Step 1: Given data

Concentration of nitrous acid (Ca): 0.010 M

pH of the solution: 2.70

Step 2: Write the acid dissociation reaction

Nitrous acid is a weak acid that dissociates according to the following expression.

HNO₂ ⇄ H⁺ + NO₂⁻

Step 3: Calculate the concentration of H⁺

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -2.70 = 2.00 × 10⁻³ M

Step 4: Calculate the acid dissociation constant (Ka)

For a weak acid, we can calculate Ka using the following expression.

Ka = [H⁺]²/Ca

Ka = (2.00 × 10⁻³)²/0.010

Ka = 4.0 × 10⁻⁴

5 0

3 years ago

Given: N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in t

guapka [62]

The given chemical reaction is:

$N_{2}+3Cl_{2}-->2NCl_{3}$

Δ $H^{0}_{reaction}=$ ∑BE(reactants)-∑BE(products)

= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

= 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine = $85.3 g Cl_{2}* \frac{1 mol Cl_{2}} {70.91 g Cl_{2} }$

= 1.20 mol $Cl_{2}$

Heat change when 1.20 mol chlorine reacts

= $1.20 mol * \frac{467kJ}{mol} =560.4 kJ$

6 0

3 years ago

A thin-walled sphere rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic ener

ICE Princess25 [194]

Explanation:

The kinetic energy of translation

$E_1=\frac{1}{2}mv^2$

m= mass v= linear velocity

The kinetic energy of rotation

$E_2=\frac{1}{2}I\omega^2$

I= MOI of the thin walled sphere =kmR^2

where ω= v/R= angular velocity

$E_2=\frac{1}{2}kmR^2\frac{v}{R}^2$

Then

$\frac{E_1}{E_2} = \frac{0.5mv^2}{0.5kmR^2\frac{v}{R}^2 }$

=1/k

solid sphere: k=0.4; E1/E2 =1/0.4 = 2.5;

hollow sphere: k=2/3; E1/E2 = 1.5

3 0

3 years ago

CHEMISTRY HELP <br><br> I don't understand this....please help? thank you in advance

Igoryamba

60 i believe i haven't did science in a while sorry if im wrong though... ._.

6 0

3 years ago