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Black_prince [1.1K]
3 years ago
13

Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
6 0

Answer:

ANSWER IS 4

Step-by-step explanation:

WARRIOR [948]3 years ago
4 0

Hello there! Your answer should be 4 mph. Reasoning:

2 = (20 - x) * t 

3 = (20 + x ) * t 

Time is the same for both equations. Solve for T.

2/(20-x) = 3/(20+x)

the answer is 4 mph.

Please tell me if I was right!

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3 years ago
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kiyo bought a pizza for 12.75 and four medium drinks to Pauli’s pizza. Define a variable and write an expression to represent th
Stels [109]

The total cost, if one drink costs $3 is $27.75

  • Let the cost of a pizza be x

  • Let the cost of a drink be y

If kiyo bought a pizza for 12.75 and four medium drinks to Pauli’s pizza, this expressed as x + 4y

Since a pizza costs $12.75, hence x = $12.75

The function becomes 12.75 + 5y

f(y) = 12.75 + 5y

To get the total cost if one drink costs $3, hence;

f(3) = 12.75 + 5(3)

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f(3) = 27.75

Hene the total cost, if one drink costs $3 is $27.75

Learn more on function here: brainly.com/question/9418047

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2 years ago
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Allushta [10]

Answer:

Step-by-step explanation:

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4 0
1 year ago
Is (x-4) a factor of f(x) = x3 - 2x2 + 5x + 1? Use either the remainder theorem or the factor theorem to explain your reasoning.
Virty [35]

Answer:

(x-4) is not a factor of f(x)=x³-2x²+5x+1

Step-by-step explanation:

Uding the remainder theorem,(x-4) is a factor if the remainder is 0

Plug in x=4

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11

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Answer: The factorization of  28+56t+28w =28(1+2t+w)

The factors of 28+56t+28w are 28 and 1+2t+w.

Step-by-step explanation:

The given expression : 28+56t+28w

To factorize it, we need to find the common factor.

As 56 can be written as 2 x 28.

So, the above expression would become

28+2\times28t+28w

Now, taking 28 as common from all the terms, we will get

28(1+2t+w)

Thus, the factorization of  28+56t+28w =28(1+2t+w)

And the factors of  28+56t+28w are 28 and 1+2t+w.

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