1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zavuch27 [327]
3 years ago
6

Find the product. (3x2+6x-5)(-3x) PLEASE HELP!!! ASAP!!!

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0

Answer:

\boxed{-9x^3-18x^2 + 15x}

Step-by-step explanation:

(3x²+6x-5)(-3x)

Apply distributive law.

-3x(3x²)-3x(6x)-3x(-5)

Simplify.

-9x³ - 18x² + 15x

VashaNatasha [74]3 years ago
5 0

Answer:

\boxed{\red{  - 9 {x}^{3}  - 18 {x}^{2}  + 15x}}

Step-by-step explanation:

( - 3x)(3 {x}^{2}  + 6x - 5) \\ - 3x(3 {x}^{2} ) - 3x(6x) - 3x( - 5) \\  =  - 9 {x}^{3}  - 18 {x}^{2}  + 15x

You might be interested in
What is the value of -4.4+ (5-2)(-6)?
Pachacha [2.7K]

Answer:

Step-by-step explanation:

-4.4 + (5-2)(-6) = -4.4 + (3)(-6) = -4.4 + (-18) = - 22.4

8 0
3 years ago
Read 2 more answers
PLEASE NEED HELP ASAP IM GIVING ALL MY POINTS THIS SHOULD BE A EASY QUESTION.​
faust18 [17]

Answer:

  1. Function 1 is not a function.
  2. The domain and range of the first function respectively are \text{ \{-3, 0, 1, 5\}} and \text{ \{-4, -2, -1, 1, 3\}}.
  3. Function 2 is a function.
  4. The domain and range of the second function respectively are \text{ \{-2, -1, 0, 1, 2\}} and \text{ \{-7, -2, 1\}}.

Step-by-step explanation:

In math, every function has a domain and a range.

  • The domain of the function is all of the x-values for which the function is true. These can be found on the x-axis for every position at which the function exists or crosses the x-axis.
  • The range of the function is all of the y-values for which the function is defined. The range can be found in the same manner as the domain - for every y-value at which the function exists, it is apart of the range.

Therefore, with this information given to us, we need to also know about coordinate pairs. Coordinate pairs are written in (x, y) form.

Functions are classified in four ways:

  1. One-to-one functions: Functions are considered to be one-to-one functions if there are unique y-values (no y-values are repeated) and there is one x-value for every one y-value.
  2. Onto functions: Functions are considered to be onto functions if there are unique x-values. These x-values cannot repeat, but different x-values can be connected to the same y-values.
  3. Both one-to-one & onto: Functions are considered both one-to-one and onto when there is exactly one x-value for every one y-value.
  4. Neither one-to-one or onto: Functions are considered to be neither an one-to-one function or an onto function when they have two or more of the same y-values assigned to the same x-values. A function cannot exist if y-values are duplicated on a x-value.

Finally, the domain and range should be written in ascending order. Therefore, the lowest number should be written first in the domain and the highest number should be written last.

<u>Function 1</u>

We are given the function: \text{ \{(-3, 3)}, (1, 1), (0, -2), (1, -4), (5, -1) \} }.

Using the information above, we can pick out our x and y-values from the function.

Values of Domain: -3, 1, 0, 1, 5

Values of Range: 3, 1, -2, -4, -1

Now, we need to arrange these in ascending order.

Domain Rearranged: -3, 0, 1, 1, 5

Range Rearranged: -4, -2, -1, 1, 3

Using these values, we can see what values we have.

For x-values:

x = -3: 1 value

x = 0: 1 value

x = 1: 2 values

x = 5: 1 value

For y-values:

y = -4: 1 value

y = -2: 1 value

y = -1: 1 value

y = 1: 1 value

y = 3: 1 value

Therefore, we can begin classifying this function. Because we have all separate y-values, we have a function. However, we have two of the same x-value, so we have an onto function.

Now, we can create our domain and range in the set. We use the same formatting given for the first function. We list the values in ascending order and list them in brackets to show that they are apart of a set.

The domain values are the x-values, so they are \text{ \{-3, 0, 1, 5\}}.

The range values are the y-values, so they are \text{ \{-4, -2, -1, 1, 3\}}.

Therefore, the domain and range for function one are defined, but this is not a function. Because the x-values repeat, it cannot be a function.

<u>Function 2</u>

We are given a table of values that needs to be translated into the set notation. This makes it easier to identify the values. We are given x-coordinates in the top row and y-coordinates in the bottom row. And, the table is set up to where the x-value directly above the y-value makes a coordinate pair. Using this, we can create the set function.

The set function is \text{ \{(-2, -7), (-1, -2), (0, 1), (1, -2), (2, -7)\}}.

Now, we can use the same method as above to pick out the x and y-values and reorder them to be from least to greatest.

Values of Domain: -2, -1, 0, 1, 2

Values of Range: -7, -2, 1, -2, -7

Now, we rearrange these.

Domain Rearranged: -2, -1, 0, 1, 2

Range Rearranged: -7, -7, -2, -2, 1

Now, we can check how many times the function presents each coordinate.

For x-values:

x = -2: 1 value

x = -1: 1 value

x = 0: 1 value

x = 1: 1 value

x = 2: 1 value

For y-values:

y = -7: 2 values

y = -2: 2 values

y = 1: 1 value

Now, we can classify the function. The x-values are unique, but the y-values are repeated. Therefore, because the x-values are assigned to one y-coordinate and they are unique, this is not an one-to-one function. Additionally, it cannot be an onto function because the y-values are not unique - they are repeated. Therefore, it is neither an one-to-one function or an onto function. If this function were graphed, it would actually reveal a parabola. However, it is still a function.

The domain values are the x-values, so they are \text{ \{-2, -1, 0, 1, 2\}}.

The range values are the x-values, so they are \text{ \{-7, -2, 1\}}.

8 0
2 years ago
Describe the graph of y={1/(2x-10)}-3 compared to the graph of y=1/x
tester [92]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)=  A(  Bx+  C)+  D&#10;\\\\&#10;~~~~y=  A(  Bx+  C)+  D&#10;\\\\&#10;f(x)=  A\sqrt{  Bx+  C}+  D&#10;\\\\&#10;f(x)=  A(\mathbb{R})^{  Bx+  C}+  D&#10;\\\\&#10;f(x)=  A sin\left( B x+  C  \right)+  D&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\&#10;\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }  B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\&#10;~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\&#10;~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }  D\\&#10;~~~~~~if\   D\textit{ is negative, downwards}\\\\&#10;~~~~~~if\   D\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind, let's check these two

\bf \stackrel{parent}{y=\cfrac{1}{x}}\qquad \qquad\qquad \qquad  \stackrel{transformed}{y=\cfrac{1}{\stackrel{B}{2}x\stackrel{C}{-10}}\stackrel{D}{-3}}\\\\&#10;-------------------------------\\\\&#10;B=2\qquad \textit{shrinks horizontally by }\frac{1}{2}&#10;\\\\\\&#10;C=-10\qquad \cfrac{C}{B}=\cfrac{-10}{2}\implies -5\qquad \textit{horizontally right-shifted by }5&#10;\\\\\\&#10;D=-3\qquad \textit{vertically down-shifted by }3
7 0
3 years ago
Marti is filling a 10– inch diameter ball with sand to make a medicine ball that can be used for exercising. To determine if the
Mice21 [21]

Answer:

Option A. 30\ pounds

Step-by-step explanation:

step 1

Find the volume of the sphere ( medicine ball)

The volume is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=10/2=5\ in ----> the radius is half the diameter

Convert inches to feet

Remember that

1 ft=12 in

r=5\ in=5/12\ ft

assume

\pi=3.14

substitute

V=\frac{4}{3}(3.14)(5/12)^{3}

V=0.3029\ ft^{3}

step 2

Find the weight of the ball

Multiply the volume in cubic foot by 100

0.3029*100=30.29\ pounds

Round to the nearest pound

30.29=30\ pounds

6 0
3 years ago
What type of graph organizes data into 4 groups of equal size, and is often used to compare two sets of data.
aliina [53]

The plot that organizes the data into 4 groups of equal sizes is box and whisker plot.

The image below shows a box and whisker plot. Following are the elements of box and whisker plot:

Minimum = This is the smallest value of the data set

Q1 = First (Lower) Quartile of the data set. 25% of the data values lie below this point

Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point

Q3 = Third (Upper) Quartile of the data set. 75% of the data values lie below this point.

Maximum = This is the maximum value of the data set.

Based on box and whisker plot we can compare two or more sets of data by comparing the spread of the data. We can also directly observe from the box and whisker plot if the data is uniform, normal or skewed. Using box and whisker plot we can also visualize any outliers that may be in the data.

8 0
3 years ago
Other questions:
  • I need answers plz here is the questions 80=-39+c
    8·1 answer
  • What is the value of t in the equation t+5=-25
    15·2 answers
  • Whick is larger 3kL or 30000 L?
    13·2 answers
  • Which graph represents the solution to the system of inequalities?
    8·2 answers
  • Use a geometric model to factor x^2-6x+8
    9·1 answer
  • A random sample of 81 automobiles traveling on a section of an interstate showed an average speed of 60 mph. The distribution of
    15·1 answer
  • Which of the following numbers is not part of the solution to x&gt;1?<br> 1<br> 1.2<br> 4<br> 8
    9·2 answers
  • Give an example of a function F(x) that is an antiderivative of f(x) = 9 cos(9x)+ 3x^2
    14·2 answers
  • 25(x+5\4)^2-16(x7\4)^2 factorize the expression​
    10·1 answer
  • Please help i will mark brainliest!!! i would appreciate it sm ​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!