In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
1 answer:
Answer:
L = 10.64°
Step-by-step explanation:
From the given information:
In triangle JKL;
line k = 9.6 cm
line l = 2.7 cm; &
angle J = 43°
we are to find angle L = ???
We can use the sine rule to determine angle L:
i.e

Using Pythagoras rule to find j
i,e
j² = k² + l²
j² = 9.6²+ 2.7²
j² = 92.16 + 7.29
j² = 99.45

j = 9.97
∴



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