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PIT_PIT [208]
4 years ago
11

The graph of f(x) = log x + 3 is the graph of g(x) = log x translated 3 units |

Mathematics
2 answers:
vesna_86 [32]4 years ago
5 0

Answer: 3 units up //

Step-by-step explanation:

Tasya [4]4 years ago
5 0

Answer:

1. up

2. add 3 to the y-coordinate

3. b

Step-by-step explanation:

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3 years ago
Suppose that lithium calculator battery with a charge of 3 volts, actually has a voltage with uniform distribution between 2.93
Dmitrij [34]

Answer:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

M = \frac{a + b}{2}

The standard deviation of the uniform distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Uniform distribution between 2.93 and 3.1 volts

This means that a = 2.93, b = 3.1. So

Mean:

M = \frac{2.93 + 3.1}{2} = 3.015

Standard deviation:

S = \sqrt{\frac{(3.1 - 2.93)^{2}}{12}} = 0.049

What is the probability that a battery has a voltage less than 2.98?

P(X \leq 2.98) = \frac{2.98 - 2.93}{3.1 - 2.93} = 0.2941

So the correct answer is:

b. E(X) = 3.015, STDEV(X)= 0.049, P (X ≤ 2.98) = 0.2941

6 0
3 years ago
Tyler poured 15 cups of water into 2 equal-sized bottles and filled each bottle. How much water was in each bottle?
LiRa [457]

Answer:

7.5

Step-by-step explanation:

If there are 2 bottles and 15 cups then...  

15 ÷ 2 = 7.5  

He poured 7.5 cups of water in each bottle.

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2 years ago
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Step-by-step explanation:

ahaha but for real it is 19

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3 years ago
Luetta is shopping and find a $200 video game that is mark down by 5% how much will be taken off the price in dollars
viva [34]

Answer:

$10.00

Step-by-step explanation:

$200 x . 05 = $10.00

5 0
3 years ago
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