3 years ago

5^(11x+23)=125^(7x) how to solve for x

1 answer:

8 0

Answer: x= 23/10 or x= 2.3
First... 5^11x-23=5^21x
Cancel out the 5
Secondly... 11x+23 =21x
Switch 21 and 23 to make...
11x=21x-23. Switch again to make...
11x-21x=23
Now subtract 11 and 21
-10x=-23
Divide to get
x=23/10 or x=2.3

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Your friend claims that when a polynomial function has a leading coeffcient of 1 and the coefficients are all integers , every p

sammy [17]

Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>

It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every <u>possible rational root</u> is the format $\frac{p}{q}$ .

In this problem:

The leading coefficient is 1, hence it's only factor is $q = 1$ , thus guaranteeing that every possible rational zero is an integer, which means that your friend is correct.