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3 years ago

Use the quadratic formula to find solutions to the quadratic equation given below. 2x2+x-1=0

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

<u>Answer</u>:

$\boxed{x = \frac{1}{2}} \text{and} \boxed{x = - 1}$

<u>Step-by-step explanation:</u>

The quadratic formula is: $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ .

So plugging in all the values, we are left with $\frac{-1 \pm 3}{4}.$

Then, we can solve for both values of x, which are $x = 1/2$ and $x = -1$

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Answers before 8pm pleasee !!

otez555 [7]

Answer:

-8 and -1

Step-by-step explanation:

3 0

3 years ago

Work out the gradient of the straight line that passes through (2,6) and (6,12)

Furkat [3]

Answer:

The gradient of the straight line that passes through (2, 6) and (6, 12) is $m = \frac{3}{2}$ .

Step-by-step explanation:

Mathematically speaking, lines are represented by following first-order polynomials of the form:

$y = b + m\cdot x$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$m$ - Slope.

$b$ - Intercept.

The gradient of the function is represented by the first derivative of the function:

$y' = m$

Then, we conclude that the gradient of the staight line is the slope. According to Euclidean Geometry, a line can be form after knowing the locations of two distinct points on plane. By definition of secant line, we calculate the slope:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of point A.

$x_{B}$ , $y_{B}$ - Coordinates of point B.

If we know that $A(x,y) = (2,6)$ and $B(x,y) = (6,12)$ , then the gradient of the straight line is:

$m = \frac{12-6}{6-2}$

$m = \frac{6}{4}$

$m = \frac{3}{2}$

The gradient of the straight line that passes through (2, 6) and (6, 12) is $m = \frac{3}{2}$ .

5 0

3 years ago

Can someone please help me with math.

tensa zangetsu [6.8K]

I think is A or c for number 2 and number 1 A or d I am not sure

8 0

3 years ago

Solve this system of equations by graphing. First graph the equations, and then type the solution.

stealth61 [152]

Answer:

The solution is the point (1,-4)

Step-by-step explanation:

we have

$y=-3x-1$ ----> equation A

$y=-2x-2$ ----> equation B

we know that

The solution of the system of equations by graphing is the intersection point both graphs

using a graphing tool

The intersection point is (1,-4)

see the attached figure

therefore

The solution is the point (1,-4)

5 0

3 years ago

Determine if the two lines with the given slope are parallel, perpendicular, or neither. Circle your

Sati [7]

Answer:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

Step-by-step explanation:

Given

m₁ = 3/2

m₂ = -3/2

We know that when two lines are parallel, they have equal slopes

But

m₁ ≠ m₂

3/2 ≠ -3/2

As the m₁ and m₂ are not equal.

Hence, the lines are not parallel.

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = 3/2 × -3/2

= -9/4

= -2.25

m₁ × m₂ ≠ -1

Thus, the lines are not perpendicular.

Conclusion:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

8 0

2 years ago