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3 years ago

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Which pair of properties apply to both sound and electromagnetic waves? A) Both waves carry energy and refract. B) Both waves ar

e longitudinal and carry energy. C) Both waves are transverse and need a medium. D) Both waves carry energy and do not need a medium to travel through.

2 answers:

dsp733 years ago

5 0

Answer:

A) Both waves carry energy and refract.

Explanation:

<u>Sound waves are longitudinal waves</u>, and <u>electromagnetic waves are transverse waves</u>. So as they are a different type of wave we discard options B and C.

Also sound waves unlike electromagnetic waves, they do need a medium to propagate, which discards option D.

This leads us to the correct option that is A. Both waves carry energy and refract.

All waves are a perturbation that carries energy. Also, refraction occurs in both types of waves, this because both change direction when moving from one medium to another.

Alecsey [184]3 years ago

3 0

Answer:

A. Both waves carry energy and refract is the correct answer.

Explanation:

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A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on

Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

$K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

I is the moment of inertia, $I=mr^2$

Since, $\omega=\dfrac{v}{r}$

$K_i=mv^2$

$K_i=96\times (0.24)^2=5.529\ J$

Finally it stops, so the final energy of the hoop will be, $K_f=0$

The work done by the hoop is equal to the change in kinetic energy as :

$W=K_f-K_i$

W = -5.529 Joules

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3 years ago

Why the eye is an organ give reason

Ilia_Sergeevich [38]

Answer:

Explanation:

organ give reason

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3 years ago

You find a bag labeled "10 kg of lead-210". Its contents now weigh 1.25 kg. How many half-life periods have there been since the

zlopas [31]

Answer : The number of half-life periods will be, 3

Explanation : Given,

Initial amount of lead = 10 kg

Amount of lead after decay = 1.25 kg

Half-life = 22 years

Formula used :

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives

$a_o$ = Initial amount of the reactant

n = number of half lives

$t_{1/2}$ = half-life

Now put all the given values in the above formula, we get:

$1.25=\frac{10}{2^n}$

$2^n=8$

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$n=3$

Thus, the number of half-life periods will be, 3

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4 years ago

A block of mass 5.6 kg is attached to a horizontal spring on a rough floor. Initially the spring is compressed 3.5 cm. The sprin

Mariana [72]

Answer:

The velocity of block = 0.188 $\frac{m}{s}$

Explanation:

Mass m = 5.6 kg

k = 1040 $\frac{N}{m}$

$\mu$ = 0.26

$x_{1} =$ 0.035 m , $v_{1}$ = 0

$x_{2} =$ 0.02 m

From work energy theorem

$K_{1} + U_{1} + W_{other} = K_{2} + U_{2}$ --------- (1)

Kinetic energy

$K = \frac{1}{2} k x^{2}$ ------- (1)

Potential energy

$U = \frac{1}{2} k x^{2}$ ------- (2)

Work done

W = F.s ------ (3)

From Newton's second law

$R_{N}$ = mg

$R_{N}$ = 5.6 × 9.81 = 54.9 N

Friction force = 0.4 × 54.9 = 21.9 N

Now the work done by the friction

$W_{f}$ = - 21.9 × 0.015

$W_{f}$ = - 0.329 J

Now kinetic energy

At point 1

$K_{1} = \frac{1}{2} m v^{2} _{1}$

$K_{1} = 0$

$U_{1} = \frac{1}{2} k x^{2}$

$U_{1} = \frac{1}{2} (1040) 0.035^{2}$

$U_{1} =$ 0.637 J

At point 2

$K_{2} = \frac{1}{2} (5.6) v^{2} _{2}$

$K_{2} = 2.8 v_{2} ^{2}$

Potential energy

$U_{2} = \frac{1}{2} k x_2^{2}$

$U_{2} = \frac{1}{2} (1040) 0.02^{2}$

$U_{2} = 0.208$ J

From equation (1) we get

0 + 0.637 - 0.329 = 2.8 $v_{2} ^{2}$ + 0.208

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4 years ago

What is the difference between em waves and mechanical waves?

Anastaziya [24]

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

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3 years ago