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shusha [124]
4 years ago
10

The vibrations along a longitudinal wave move in a direction __________. a. both along and perpendicular to the wave b. along th

e wave c. perpendicular to the wave d. None of the other answers
Physics
2 answers:
jeyben [28]4 years ago
7 0
The answer would be A or C
AURORKA [14]4 years ago
3 0

Answer:

Locard's most famous contribution to forensic science is known today as “Locard's Exchange Principle”.

Explanation:

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What is the most likely elevation of point B?<br>a. 150 ft<br>b. 200 ft<br>c. 125 ft<br>d. 225 ft​
zepelin [54]

Answer:

D

Explanation:

erm i think its 225 ft?

7 0
4 years ago
Read 2 more answers
A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb
torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

W_p = mg sin \theta

where \theta is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to W_p, in order to produce a net force of zero (and therefore, a zero acceleration).

8 0
4 years ago
Sea and land breezes over a large region that change direction with the seasons are called_____________.
Nataliya [291]
Monsoon. Sea and land breezes over a large region that change direction with the seasons are called. Global winds.
8 0
3 years ago
Which is a unit rate
avanturin [10]
D. 18 miles driven in a week

6 0
3 years ago
Read 2 more answers
A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Marianna [84]

Answer:

Part a)

Final speed of the corn is 19.05 m/s

Part b)

Kinetic energy of the corn is 3.1 J

Explanation:

Part a)

As we know that the initial position of the corn is

h = 18.5 m

now we also know that it will fall from rest and moving under constant acceleration so we will have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(9.81)(18.5)

v_f = 19.05 m/s

Part b)

Kinetic energy of the corn is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.017)(19.05)^2

K = 3.1 J

4 0
4 years ago
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