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maw [93]
3 years ago
9

What is the difference between em waves and mechanical waves?

Physics
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

Since electromagnetic waves do not require a medium to pass through, they are faster in matter that has fewer particles. ... ~ Sound cannot travel in a vacuum because mechanical waves, such as sound waves, require a medium to propagate through.

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Only about 10% of the electromagnetic energy from an incandescent lightbulb is visible light. The bulb radiates most of its ener
AlekseyPX

Answer:

<em>1. 1.48 W/</em>m^{2}<em></em>

<em>2. 4.93 x </em>10^{-9}  J/m^{3}<em></em>

<em>3. 33.3 V/m</em>

<em>4. 1.11 x </em>10^{-7} T<em></em>

Explanation:

The step by step explanation to the question is contained in the attached images;

3 0
3 years ago
Read 2 more answers
According to the universal law of gravitation _____.
KiRa [710]
According to the universal law of gravitation, all particles attract every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. So the answer here would be, 

a. everything has a gravitational force because everything has mass.
6 0
3 years ago
Read 2 more answers
The atmosphere pressure can support mercury in a tube, which the upper end is closed, up to 0.76 meter. If the mercury is replac
Leni [432]

Answer:

Maximum height the atmosphere pressure can support the

water=10.336 m

Explanation:

We know that ,

Pressure = h\cdot\rho\cdot g

Case 1 - Mercury in the tube

Density\ of\ mercury =\rho_1\\and\ height\ attained\ for\ mercury\ column = h_1

Case 2 - Water in the tube

Density\ of\ water =\rho_2\\and\ height\ attained\ for\ water\ column = h_2

Since atmospheric pressure is same

.P=h_1\cdot\rho_1\cdot g = h_2\cdot\rho_2\cdot g

or,  h_2=\frac{h_1\rho_1}{\rho_2}

Given\ h_1= 0.76\  m,\rho_1=13.6\cdot\rho_2

∴ h_2=0.76\cdot13.6=10.336\ m

Hence height of the water column =10.336 m

6 0
4 years ago
A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force
Sauron [17]

Answer:

The acceleration is 2.448 meters per square second and is vertically upward.

Explanation:

The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:

\Sigma F = F - m\cdot g = m\cdot a (1)

Where:

F - Buoyant force, measured in newtons.

m - Mass of the plastic ball, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

a - Net acceleration, measured in meters per square second.

If we know that F = 5\,N, m = 0.408\,kg and g = 9.807\,\frac{m}{s^{2}}, then the net acceleration of the plastic ball is:

a = \frac{F}{m} - g

a= 2.448\,\frac{m}{s^{2}}

The acceleration is 2.448 meters per square second and is vertically upward.

4 0
3 years ago
A man 6.00 ft tall approaches a street light 15.0 ft above the ground at the rate of 4.00 ​ft/s. How fast is the end of the​ man
klio [65]

Answer:

\frac{dx}{dt} = 10 ft/s

Explanation:

As per given figure let say the tip of the shadow is at distance "x" from the base of the lamp

so here we have

\frac{x}{15} = \frac{x - y}{6}

so we have

6x = 15 x - 15 y

15 y = 9 x

now we have

5\frac{dy}{dt} = 2\frac{dx}{dt}

5(4) = 2\frac{dx}{dt}

\frac{dx}{dt} = 10 ft/s

7 0
3 years ago
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